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WARRIOR [948]
3 years ago
7

Question 1 (1 point)

Mathematics
1 answer:
Leni [432]3 years ago
6 0
<h3>▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪</h3><h3 /><h3><u>Question</u> 1 </h3>

Money spent semi - annually (in 6 months) = $ 150

So, money spent annually (12 months) is equal to :

  • 150 \times 2

  • \$ \: 300
<h3><u>Question</u> 2</h3>

Her budget annually (in 12 months) = $ 900

So, budget monthly is equal to :

  • \dfrac{900}{12}

  • \$ \: 75
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Please solve for a, b, and c
rusak2 [61]

The table is:
Number of washes denoted by x: 0, 8, 12
Amount left on card denoted by y: 30, 18, 12
 
a.       Write an equation that shows the amount of dollars left on the card
Solution:
18 – 30 divided by 8 – 0 = -12/8
On simplest form is -3/2
 
The equation is y = -3/2x + 30
 
b.      Explain the meaning of the negative slope above.
As the number of car washes increase, the dollars left on the card decreases.
 
c.       What is the maximum value of x?
0 = -3/2x + 30
2/3 x 3/2 x = 30/1 x 2/3
Cancel 2/3 x 3/2 and reduce 30 by 3 we get 10, 10 x 2
x = 20

Read more on Brainly.com - brainly.com/question/7171213#readmore
3 0
3 years ago
What is 7.2 times 10 to the 7th power times 14.6 x 10 to the 5th power?
Alexxx [7]

7 x 10^{7}  times 14.6 x10^{5}

<em>Multiply 7 and 14.6 and add exponents</em>

Final Answer 102.2 and 10^{5}

hope that helps :)

6 0
3 years ago
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10) Solve the temperature formula for F.
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Find the 92nd term of the arithmetic sequence 11, 19, 27, ...
arlik [135]

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The 92nd term of the arithmetic sequence is 731 because the common difference between them is 8 and then I added 8 with every single number that I got and I continued adding until I get my 92nd term which is 731.

6 0
3 years ago
7. License Plate Laws The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we con
sergejj [24]

Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let p_{1} be the probability that commercial cars have rear license plates and p_{2} be the probability that connected trucks have rear license plates.

                         Cars                     Trucks                         Total

Total                  2049                    334                             2383

x                          239                      45                                284

p                        0.1166                   0.1347                          0.1191

α=0.05

Hypothesis will be  :

H_{0}:p_{1} =p_{2}

H_{1} :p_{1} < p_{2}

It is a left tailed test at 0.05 significance.

Standard errors of p=\sqrt{p(1-p)/n}

=\sqrt{(0.1191*0.8809)/2383}

=\sqrt{0.1049/2383}        

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so  we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

Learn more about z test at brainly.com/question/14453510

#SPJ4

5 0
2 years ago
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