3 years ago

Look at screenshot please

1 answer:

3 0

I think the correct is c

You might be interested in

Usimov [2.4K]

Answer: $(188.24,\ 211.76 )$ .

Step-by-step explanation:

Given : Sample size : n= 64 , the sample is a large sample (n>30), so we can apply z-test.

Sample mean = $\overline{x}=200$

Standard deviation : $\sigma=48$

Level of confidence: $1-\alpha=0.95$

$\Rightarrow\ \alpha=0.05$

Then, critical z-value = $z_{\alpha/2}=1.96$

The confidence interval to estimate the population mean is given by :_

$\overline{x}\ \pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

$=200\ \pm\ (1.96)\dfrac{48}{\sqrt{64}}\\\\=200\pm11.76=(200-11.76, 200+11.76)=(188.24,\ 211.76 )$

Hence, the 95% confidence interval to estimate the population mean can be computed as $(188.24,\ 211.76 )$ .

7 0

3 years ago

Oksi-84 [34.3K]

As 0.1333 is less than 0.5 the answer is

375

3 0

3 years ago

kvasek [131]

= it is equal to because the absolute value of |-5| is 5

6 0

2 years ago

Mashutka [201]

Answer:

Step-by-step explanation:

Incomplete question.

5 0

3 years ago

vovangra [49]

Answer:

I believe this is a METAPHOR cause you cant really throw your voice as rope.

4 0

3 years ago