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Greeley [361]
3 years ago
14

How did the temperature structure of the solar nebula determine planetary composition?

Physics
1 answer:
STALIN [3.7K]3 years ago
3 0

Explanation:

The temperature of the solar nebula was decreasing as it moved away from its center. Therefore, only heavy elements could condense in the inner solar system and terrestrial planets could not form with light elements, such as gases. In the outer solar system, the Jovian planets formed mostly with gases, since temperatures were too low to allow rocky compositions.

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I need help with this please thank you!
Tresset [83]

D. A beam balance does not measure mass; it measures weight. The gravitational force of attraction between the earth and an object depend on the mass of the object. ... The beam balance measures the force F exerted by the mass on the beam balance

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Which statement is correct about the car?
JulijaS [17]

Answer:

B

Explanation:

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3 years ago
You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo
S_A_V [24]

Answer:

A.  Z = 185.87Ω

B.  I  =  0.16A

C.  V = 1mV

D.  VL = 68.8V

E.  Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

Z=\sqrt{R^2+\omega^2L^2}       (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

I=\frac{V}{Z}                     (2)

V: voltage amplitude = 30.0V

I=\frac{30.0V}{185.87\Omega}=0.16A

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV            (3)

D. The voltage across the inductor is:

V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V

E. The phase difference is given by:

\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°

5 0
3 years ago
An atomic nucleus is composed of
musickatia [10]

Answer:

84 protons and 128 neutron

8 0
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