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3 years ago

I need help with this please thank you!

Physics

1 answer:

Tresset [83]3 years ago

8 0

D. A beam balance does not measure mass; it measures weight. The gravitational force of attraction between the earth and an object depend on the mass of the object. ... The beam balance measures the force F exerted by the mass on the beam balance

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If 40.0 kj of energy are absorbed by .500 kg of water 10 degrees c, what is the final temperature of the water?

anastassius [24]

To solve the problem, we must use the following equation:

$Q=mC_s (T_f -T_i)$

where

Q is the amount of heat energy absorbed by the water

m is the mass of the water

Ti and Tf are the initial and final temperature

Cs is the specific heat capacity of the water

The data we have in this problem are:

Q=40.0 kJ

$C_s =4.186 kJ/kg^{\circ}C$

$T_i=10^{\circ}C$

m=0.500 kg

Substituting the data into the equation and re-arranging it, we find

$T_f = T_i + \frac{Q}{mC_s}=10^{\circ}+\frac{40.0 kJ}{(0.500 kg)(4.186 kJ/kg^{\circ}}=29.1^{\circ}C$

So the final temperature of the water will be 29.1 degrees.

8 0

3 years ago

53. A recently discovered planet has a mass four times as great as Earth's and a radius twice as large as Earth's. What will be

marusya05 [52]

Answer:

$g' = g = 9.81 m/s^2$

so gravity will be same as that of surface of earth

Explanation:

As we know that the acceleration due to gravity is given as

$g = \frac{GM}{R^2}$

here we have

$M = 4M_e$

$R = 2R_e$

we know that for earth we have

$g = 9.81 = \frac{GM_e}{R_e^2}$

now if the radius and mass is given as above

$g' = \frac{G(4M_e)}{(2R_e)^2}$

$g' = \frac{GM_e}{R_e^2}$

$g' = g = 9.81 m/s^2$

so gravity will be same as that of surface of earth

6 0

3 years ago

Basile [38]

Answer:

T = 0.01 s

Explanation:

Given that,

The frequency of the beats of a hummingbird, f = 100 Hz

We need to find the period of the hummingbirds flaps. Let the time is t. We know that the relation between frequency and time period is given by :

T = 1/f

Put all the values,

T = 1/100 = 0.01 s

So, the time period of the humming bird is 0.01 s.

3 0

3 years ago

A block of mass

Gennadij [26K]

(a) The work done by the applied force is 26.65 J.

(b) The work done by the normal force exerted by the table is 0.

(d) The work done by the net force on the block is 26.65 J.

<h3>Work done by the applied force</h3>

W = Fdcosθ

W = 14 x 2.1 x cos25

W = 26.65 J

<h3>Work done by the normal force</h3>

W = Fₙd

W = mg cosθ x d

W = (2.5 x 9.8) x cos(90) x 2.1

W = 0 J

<h3>Work done force of gravity</h3>

The work done by force of gravity is also zero, since the weight is at 90⁰ to the displacement.

<h3> Work done by the net force on the block</h3>

∑W = 0 + 26.65 J = 26.65 J

Thus, the work done by the applied force is 26.65 J.

The work done by the normal force exerted by the table is 0.

The work done by the force of gravity is 0.

The work done by the net force on the block is 26.65 J.

Learn more about work done here: brainly.com/question/8119756

#SPJ1

6 0

2 years ago

Quasar spectra often show many absorption lines that all appear to be as a result of the same electron transition (such as level

Elanso [62]

Answer: Because of different redshift of cloud.

Explanation:

We are seeing absorption lines from clouds of gas that lie between us and the quasar, and therefore each cloud has a different redshift.

A quasar's spectrum is hugely redshifted. And most astronomers think this large redshift tells us about the distance to the quasar.

5 0

3 years ago