(C) "serpentine"
Serpentine is a winding word. The phrase would read "The mountain road was distinctly serpentine: it twisted back and forth along the contours of the hillside" if this term were added to the text.
The comma denotes that the meaning of the omitted phrase will be clarified in the second clause of the sentence. Because a winding road does actually curve "back and forth," the word "serpentine" matches the text. The answer is not (A).
A panoramic view is one that encompasses the entire surrounding region. (B) is the wrong answer. Precipitous refers to a steep slope. The answer is not (D). The term "circumscribed" describes something that is restrained or encircled by a line. The answer is not (E). Moving backward is referred to as retrograding.
Here's another question with an answer similar to this about passage analysis: brainly.com/question/3521530
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Answer:
Step-by-step explanation:
a (2³)² = 2³ˣ² = 2⁶
b (7⁰)¹ = 7⁰ˣ¹ = 7⁰ = 1
c (5⁶)³ = 5⁶ˣ³ = 5¹⁸
d (6²)⁴ = 6²ˣ⁴ = 6⁸
e (8³)⁴ = 8³ˣ⁴ = 8¹²
f (4³)² = 4³ˣ² = 4⁶
g (9¹)² = 9¹ˣ² = 9² = 81
h (3⁷)² = 3⁷ˣ² = 3¹⁴
i (10²)³ = 10²ˣ³ = 10⁶
j (11²)⁴ = 11²ˣ⁴ = 11⁸
Answer:
35°
Step-by-step explanation:
We assume that points S, T, U, V all lie on the circle.
Inscribed angle TUV intercepts long arc VST and short arc VUT. The long arc has measure 220°, so the measure of the short arc is 360° -220° = 140°.
Since chords UV and UT are the same length, point U bisects arc VUT. That means the measure of arc VU is 140°/2 = 70°.
Inscribed angle VSU intercepts arc VU, so has half the measure of the arc:
∠VSU = 70°/2
∠VSU = 35°
Read more on Brainly.com - brainly.com/question/15559971#readmore
<h3>I'll teach you how to factor 6x^2y − 3xy − 24xy^2 + 12y^2</h3>
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6x^2y − 3xy − 24xy^2 + 12y^2
Apply exponent rule:
6x^2y-3xy-24xyy+12yy
Rewrite 12 as 4*3
Rewrite -24 as 8*3
Rewrite 6 as 2*3
2*3x^2y-3xy+8*3xyy+4*3yy
Factor out common term 3y:
3y(2x^2-x-8xy+4y)
Factor 2x^2-x-8xy+4y:
3y(2x-1)(x-4y)
Your Answer Is 3y(2x-1)(x-4y)
plz mark me as brainliest if this helped :)
Answer:
Step-by-step explanation:
1.
Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.
2.
Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.
3.
Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,
4.
The same method used to solve problem (3) can be applied to this problem.