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3 years ago

Need helpppp gajsgajshajda

Mathematics

1 answer:

marissa [1.9K]3 years ago

8 0

Answer: 1.) 14.66666666666667
2.) 20

Steps:
1.) 180 = 3x + 136
180 -136 = 3x
44 = 3x
44/3 = x
14.66666666666667 = x

2.) 70 + x = 90
x = 90 - 70
x = 20

I would appreciate brainliest if this was helpful and correct! ;)

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1 year ago

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2 years ago

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igor_vitrenko [27]

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3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

8 0

3 years ago

A movie theater complex gave a poll as viewers exited from two theaters showing the same film. They had a 20% response rate from

sp2606 [1]

Answer:

Let´s define the variables:

x = number of people in theater A

y = number of people in theater B

We know that a 20% (or 0.2 in decimal form) of the people in theater A answered the survey, then the number of people from theater A that answered the survey is: Na = 0.2*x

We know that a 30% (or 0.3 in decimal form) of the people in theater B answered the survey, then the number of people from theater B that answered the survey is: Nb = 0.3*y

There where 800 people in total (counting from the two theatres)

Then x + y = 800.

A) In this case we have:

Na = Nb

this means that:

0.2*x = 0.3*y

and we also have the equation:

x + y = 800

To solve this, we need to isolate one variable in one of the equations, i will isolate x in the second equation:

x = 800 - y

And now we can replace this in the other equation to get:

0.2*(800 - y) = 0.3*y

We need to solve this for y:

160 - 0.2*y = 0.3*y

160 = 0.3*y + 0.2*y = 0.5*y

160/0.5 = y = 320

Then there where 320 people in theater B, and:

x + y = 800

x + 320 = 800

x = 800 - 320 = 480

There where 480 people in theather A.

B) Now we have:

x = 440

y = 360

then:

Na = 0.2*440 = 88

In theater A, 88 people answered the survey.

Nb = 0.3*360 = 108

In theater B, 108 people answered the survey.

In total, 88 + 108 = 196 people answered the survey.

5 0

2 years ago

Need helpppp gajsgajshajda​

Need helpppp gajsgajshajda