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Eva8 [605]
3 years ago
10

Given parallelogram ABCD with C(5,4), find the coordinates of A if the diagonals AC and BD intersect at (2,7).

Mathematics
2 answers:
finlep [7]3 years ago
8 0
Plot graph and count for A. 

A (-1,10)
Anna71 [15]3 years ago
4 0

Answer:

<h2>A (-1;10)</h2>

Step-by-step explanation:

From the problem, we deduct that point (2,7) is a middle point for diagonals AC and BD, because the intersection of diagonals in a parallelogram intercept in the middle point of each one.

So, the coordinates of A are (x,y) unknown, and coordinates of C are (5,4), applying the definition of middle point:

m_{AC}=(\frac{x+5}{2};\frac{y+4}{2} )

However we know the exact coordinates of the middle point, which are (2,7), that means:

\frac{x+5}{2}=2\\ x=4-5=-1

\frac{y+4}{2}=7\\ y=14-4=10

Therefore, the coordinates of A are (-1;10)

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Answer:

See Explanation

Step-by-step explanation:

According to the Question,

  • Given That,  ∠T and ∠S are complementary & ∠S and ∠U are complementary

Thus, m∠T + m∠S = 90 ------ Equation 1

&  m∠S + m∠U = 90  ------- Equation 2

  • Now, Subtract Equation 2 From Equation 1, we get

m∠T - m∠U = 0

Thus, m∠T = m∠U

The measure of angle T is equal to angle U.(∠U≅∠T).

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3 years ago
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7.109) The leading brand of dishwasher detergent has a 30% market share. A sample of 25 dishwasher detergent customers was taken
Rina8888 [55]

Answer:

0.9021 = 90.21% probability that 10 or fewer customers choose the leading brand

Step-by-step explanation:

For each customer, there are only two possible outcomes. Either they choose the leading brand, or they do not. The probability of a customer choosing the leading brand is independent of any other customer, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The leading brand of dishwasher detergent has a 30% market share.

This means that p = 0.3

A sample of 25 dishwasher detergent customers was taken.

This means that n = 25

a. What is the probability that 10 or fewer customers choose the leading brand?

This is:

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.3)^{0}.(0.7)^{25} = 0.0001

P(X = 1) = C_{25,1}.(0.3)^{1}.(0.7)^{24} = 0.0014

P(X = 2) = C_{25,2}.(0.3)^{2}.(0.7)^{23} = 0.0074

P(X = 3) = C_{25,3}.(0.3)^{3}.(0.7)^{22} = 0.0243

P(X = 4) = C_{25,4}.(0.3)^{4}.(0.7)^{21} = 0.0572

P(X = 5) = C_{25,5}.(0.3)^{5}.(0.7)^{20} = 0.1030

P(X = 6) = C_{25,6}.(0.3)^{6}.(0.7)^{19} = 0.1472

P(X = 7) = C_{25,7}.(0.3)^{7}.(0.7)^{18} = 0.1712

P(X = 8) = C_{25,8}.(0.3)^{8}.(0.7)^{17} = 0.1651

P(X = 9) = C_{25,9}.(0.3)^{9}.(0.7)^{16} = 0.1336

P(X = 10) = C_{25,10}.(0.3)^{10}.(0.7)^{15} = 0.0916

Then

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0001 + 0.0014 + 0.0074 + 0.0243 + 0.0572 + 0.1030 + 0.1472 + 0.1712 + 0.1651 + 0.1336 + 0.0916 = 0.9021

0.9021 = 90.21% probability that 10 or fewer customers choose the leading brand

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3 years ago
Evaluate i^31 please help
Nadya [2.5K]

ANSWER

{i}^{31}  =  - i

EXPLANATION

We want to evaluate

{i}^{31}

Use indices to rewrite the expression as:

=  {i}^{30}  \times i

We know that

{i}^{2}  =  - 1

So we rewrite the expression to obtain;

=  ({ {i}^{2}) }^{15}  \times i

This gives us;

=   {( - 1) }^{15}  \times i

This simplifies to

=  - 1 \times i

=  - i

4 0
3 years ago
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