Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
Answer:
x=-1/5
double zero
Step-by-step explanation:
(5x+1)(5x+1)
x=-1/5
double zero
U have to substitute in the values of x to get the values of y
answers in order from left to right:
4.5, 4, 3.5, 3, 2.5, 2
ex of solving process:
x+2y=7
(-2)+2y=7
2y=9
y=4.5
Answer:
a = 8
Step-by-step explanation:
-5(a + 3) = - 55
- 5a - 15 = - 55
55 - 15 = 5a
5a = 40
a = 40 : 5
a = 8
Answer:
no se ablar inglés losiento
