Answer:
a) The mass is released at t = 0 when h is minimum. Half a cycle later h reaches its maximum and another half a cycle it reaches its minimum again. Hence over one cycle, h varies with t as follows:
b) According to the graph obtained in part a), h(t) could be modeled by a cosine function shifted (translated) vertically up and horizontally to the right. Hence
Step-by-step explanation:
Answer:
-19k ≠ 0
No solutions
Step-by-step explanation:
k/4 - 5k + 1 = 1
4 (k/4 - 5k + 1 = 1)
k-20k + 4 = 4
-19k ≠ 0
Answer:
m > 1
Step-by-step explanation:
Minus 6 from both side
m = 1
Answer:
The answer is 3 hours I think.
Step-by-step explanation:
Answer:
1/6
Step-by-step explanation:
Let x represent the proportion of time the third person spends on the project. You want ...
1/2 + 1/3 + x = 1 . . . . full-time equivalents
5/6 + x = 1 . . . . simplify
x = 1/6 . . . . . . . subtract 5/6
The third person should budget 1/6 of their time to the project.
