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3 years ago

Does the point (0, 37) satisfy the equation y = 79x - -37? yes no

Mathematics

1 answer:

AlexFokin [52]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

y = 79x - -37

37 = 79(0) - - 37

37 = 0 - - 37

37 = 37

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Given the geometric sequence where a1 = 3 and r = √2 find a9

Zigmanuir [339]

Answer:

$a_9=48$

Step-by-step explanation:

we are given

sequence is geometric

so, we can use nth term formula

$a_n=a_1(r)^{n-1}$

we have

$a_1=3$

$r=\sqrt{2}$

we have to find a9

so, we can plug n=9

we get

$a_9=3(\sqrt{2})^{9-1}$

$a_9=2^4\cdot \:3$

$a_9=48$

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3 years ago

3. Let sin 21 = 0.358. What is the value of x for cos x=0.358?

r-ruslan [8.4K]

Answer:

$\cos(69)$

Step-by-step explanation:

We will use the co-function identity for sine, where:

$\sin(x)=\cos(90-x)$

Since sin(21)=0.358=cos(x). This means that:

$21=90-x$

Solve for x. Add x to both sides:

$x+21=90$

Subtract 21 from both sides:

$x=69\textdegree$

Hence:

$\sin(21)=\cos(69)\approx0.358$

6 0

3 years ago

Tell the slope of a line that contains the points (5,-3) and (7,3)

KiRa [710]

(5,-3)(7,3)
slope = (y2 - y1) / (x2 - x1)
slope = (3 - (-3) / (7 - 5) = (3 + 3) / 2 = 6/2 = 3 <==

6 0

3 years ago

Read 2 more answers

Logx - logx-1^2=2log(x-1)

myrzilka [38]

Answer:

x is approximately 2.220744

Step-by-step explanation:

This can be simplified a little using properties of logarithms, and then solve it by graphing:

$log(x)-log(x-1)^2=2\,log(x-1)\\log(x)-2\,log(x-1)=2\,log(x-1)\\log(x)=4\,log(x-1)$

So we use a graphing tool to find the intersection point of the graph of $log(x)$ , and the graph of $4\,log(x-1)$

Please see attached image for the graph and solution.

The value of x is approximately 2.220744

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3 years ago

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Write each expression below in radical form and compute the value without using a calculator.

gregori [183]

Assuming that an exponentiation sign is missing, all you need to know is that rational exponents work like this:

$a^{\frac{b}{c}}=\sqrt[c]{a^b}$

So, you have

$25^{\frac{5}{2}}=\sqrt{25^5}=\sqrt{(5^2)^5}=5^5$

And similarly,

$81^{\frac{7}{4}}=\sqrt[4]{25^7}=\sqrt[4]{(3^4)^7}=3^7$

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2 years ago

Does the point (0, 37) satisfy the equation y = 79x - -37? yes no​

Does the point (0, 37) satisfy the equation y = 79x - -37? yes no