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andreyandreev [35.5K]
3 years ago
15

Solve the system using substitution. 3x+5y=15 2x+4y=8

Mathematics
1 answer:
Minchanka [31]3 years ago
7 0

Answer:

x=10

y=-3

Step-by-step explanation:

3x + 5y= 15...eqn. 1

2x + 4y= 8...eqn. 2

multiply eqn. 1 by 2 and eqn. 2 by 3

6x + 10y = 30...eqn. 3

<u>6x</u><u> </u><u>+</u><u> </u><u>12y</u><u> </u><u>=</u><u> </u><u>24...eqn. 4</u>

0 - 2y = 6

divide both sides by the coefficient of y which is -2

<u>- 2y</u> = <u>6</u>

- 2 -2

y= -3

Put y= -3 into eqn. 1

3x + 5(-3) = 15

3x - 15 = 15

3x =15 + 15

<u>3x</u> =<u> 30</u>

3 3

x = 10

Therefore X= 10 and Y= -3

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