Answer:
it is important to learn about complex solution because polynomial equation formed over a complex number can only be solved by a complex number.
this is so because, the fundamental theorem of algebra state that every polynomial equation in one variable with complex coefficient has at least one complex solution.
Step-by-step explanation:
it is important to learn about complex solution because polynomial equation formed over a complex number can only be solved by a complex number.
this is so because, the fundamental theorem of algebra state that every polynomial equation in one variable with complex coefficient has at least one complex solution.
for example:
Given any positive integer n ≥ 1 and any choice of complex numbers a0,a1,...,an, such that an 6= 0,
the polynomial equation
anzn +···+ a1z + a0 = 0 (1) has at least one solution z ∈C.
No analogous result holds for guaranteeing that a real solution exists to Equation (1) if we restrict the coefficients a0,a1,...,an to be real numbers.
E.g., there does not exist a real number x satisfying an equation as simple as x2 + 1 = 0. Similarly, the consideration of polynomial equations having integer (resp. rational) coefficients quickly forces us to consider solutions that cannot possibly be integers (resp. rational numbers).
Answer:
23%
Step-by-step explanation:
Calculate the percentage loss as shown
percent loss = 
× 100%
loss = 14.88 - 11.45 = 3.43, hence
percent loss = 
× 100% = 23%
Answer:
fourth option
Step-by-step explanation:
Given
= 
( cross- multiply )
y(w + 2) = 2z(2x - 1) = 4xz - 2z ( divide both sides by y )
w + 2 = 
( subtract 2 from both sides )
w = - 2
I believe the answer could just be 2
