Ann got 6.25 gallons of gas at $3.12 per gallon. how much did she pay

Does anyone know how to do this please help

ICE Princess25 [194]

Step-by-step explanation:

the photo should explain

3 0

1 year ago

ET

ANEK [815]

Answer:

Step-by-step explanation:

NEED MORE INFO...

8 0

2 years ago

the difference of two numbers is 16. The greater number is 5 less than 4 times the smaller number find the numbers

inna [77]

L-s=16
4s-5=l
4s-l=5
3s=21
s=7
l-7=16
l=16+7
l=23
The smaller number is 7 and the greater number is 23

5 0

3 years ago

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

7 0

3 years ago

Pls help if you actually can

Setler79 [48]

The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.

<h3>How to identify similar triangles?</h3>

From the image attached, we see that we are given the Parallelogram GRPC. Thus;

A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.

B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;

∠CGB ≅ ∠PEB (Alternate Interior Angles)

∠BPE ≅ ∠BCG (Alternate Interior Angles)

∠GBC ≅ ∠EBP (Vertical Angles)

C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;

225/325 = PE/375

PE = 260 ft

BE/425 = 225/325

BE = 294 ft

Read more about Similar Triangles at; brainly.com/question/14285697

#SPJ1

5 0

1 year ago