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Licemer1 [7]
3 years ago
9

What is the least amount of information that you need to construct a triangle congruent

Mathematics
1 answer:
muminat3 years ago
5 0

Answer:

6 points of data, minimally.

Easiest if they are 3 points.

All data is going to be comprised of more than one unit of data itself.

For 3 points, we need 6 coordinates.

For 3 lines, we need 2 points each, and then 2 coordinates for each point.

Pretty much since any other way to describe it is relying on points, I would say 3 points, each comprised of 2 coordinates are necessary as a minimum.

Even an angle is defined from points. The angular distance between two lines relies on the two lines, which each relies on 2 points to describe, and each point is 2 coordinates.

So in a 2D space, the information required to make a figure is twice the number of vertices.

Assuming a pattern, in 3D space, a cube would be minimally determined as 8 vertices times the 3 coordinate requirements of each. 24 data points to minimally describe a cube.

“A figure can precisely and minimally be described by a number of data points equal to its vertices multiplied by the number of dimensions it exists in.”

Edit… A closed figure made only of straight line segments.

I'm sorry if it has any wrong ‍♀️

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Please help need to know the answer to this supposedly is 9 + (9x36) 333 but I don’t get it
Ahat [919]

Answer:

459

Step-by-step explanation:

First line:

clock showing 9 o'clock + clock showing 9 o'clock + clock showing 3 o'clock = 9 + 9 + 3 = 21

Second line:

The calculators look exactly the same.

3 * calculators = 30

1 calculator = 10

Third line:

1 bulb + 1 bulb - 1 bulb = 15

Since 1 bulb - 1 bulb = 0, we have 1 bulb + 0 = 15, or

1 bulb = 15

Last line:

Clock showing 9 o'clock = 9

Calculator = 10

3 bulbs = 3 * 15 = 45

Total = 9 + 10 * 45 = 9 + 450 = 459

7 0
3 years ago
The giraffe is 15 feet tall. she is 2 1/2 times as tall as the elephant. how tall is the elephant?
salantis [7]
The giraffe is about 5 feet tall
3 0
3 years ago
Read 2 more answers
(0.5n+0.3)-(0.75n-0.45) find answer
Mumz [18]
I believe your answer is -0.25n+0.75
8 0
3 years ago
Solve system of equations:<br> 4l + 8m = 40<br> 5l + 2m = 28<br> Please show steps!
ziro4ka [17]
Answer:

l = 9/2 or 4.5

m = 11/4 or 2.75

Step-by-step explanation:

4l + 8m = 40

8m = 40 - 4I

m = 5 - 0.5l

5l + 2m = 28

5l + 2(5 - 0.5l) = 28

5l + (10 - l) = 28

4l + 10 = 28

4l = 18

l = 18/4 or 9/2

l = 4.5

4l + 8m = 40

4(4.5) + 8m = 40

18 + 8m = 40

8m + 18 = 40

8m = 22

m = 22/8

m = 2.75

3 0
3 years ago
The level of nitrogen oxides (NOX) in a exhaust of cars of a particular model varies normally with mean 0.25 grams per miles and
antoniya [11.8K]

Answer:

a) 15.87% probability that a single car of this model fails to meet the NOX requirement.

b) 2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

Step-by-step explanation:

We use the normal probability distribution and the central limit theorem to solve this question.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.25, \sigma = 0.05

a. What is the probability that a single car of this model fails to meet the NOX requirement?

Emissions higher than 0.3, which is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.3 - 0.25}{0.05}

Z = 1

Z = 1 has a pvalue of 0.8417.

1 - 0.8413 = 0.1587.

15.87% probability that a single car of this model fails to meet the NOX requirement.

b. A company has 4 cars of this model in its fleet. What is the probability that the average NOX level of these cars are above 0.3 g/mi limit?

Now we have n = 4, s = \frac{0.05}{\sqrt{4}} = 0.025

The probability is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.3 - 0.25}{0.025}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

4 0
3 years ago
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