Step-by-step explanation:
3x² - 8x + 4 =
3x² - 6x -2x + 4 =
3x(x-2) -2(x-2) =
(3x -2)(x-2)
Given that,
A car uses a litre of petrol to travel 4 km.
To find,
How many litres will it use to travel 32 kilometres.
Solution,
We have,
1 litre = 4 km
or
1 km = (1/4) litre
Let it will use x litres to travel 32 km.
32 km = (32/4) litres
= 8 litres
Hence, 8 litres it will use to travel 32 km.
Answer
x = 3981071.7055
y = 3981.0717
x > y
Step by step explanation
First let's find the value of x and y by taking anti - log.
log X = 6.6
X = log^ -1 (6.6)
X = 3981071.7055
Similarly,
log Y = 3.6
Y = log ^(-1) 3.6
Y = 3981.0717
Once we found the values of X and Y , we can easily compare them.
Here x > y
Hope you will understand the concept.
Thank you. :)
First bring 3x to the other side, which will give you -2y= -16-3y. Then divide everything by -2, which will give you y=8+3/2x
I’ll do an example problem, and I challenge you to do this on your own!
4x+6y=23
7y-8x=5
Solving for y in 4x+6y=23, we can separate the y by subtracting both sides by 4x (addition property of equality), resulting in 6y=23-4x. To make the y separate from everything else, we divide by 6, resulting in (23-4x)/6=y. To solve for x, we can do something similar - subtract 6y from both sides to get 23-6y=4x. Next, divide both sides by 4 to get (23-6y)/4=x.
Since we know that (23-4x)/6=y, we can plug that into 7y-8x=5, resulting in
7*(23-4x)/6-8x=5
= (161-28x)/6-8x
Multiplying both sides by 6, we get 161-28x-48x=30
= 161-76x
Subtracting 161 from both sides, we get -131=-76x. Next, we can divide both sides by -76 to separate the x and get x=131/76. Plugging that into 4x+6y=23, we get 4(131/76)+6y=23. Subtracting 4(131/76) from both sides, we get
6y=23-524/76. Lastly, we can divide both sides by 6 to get y=(23-524/76)/6
Good luck, and feel free to ask any questions!
