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igor_vitrenko [27]

3 years ago

6

What is the image of the point (-9,-6) after a rotation of 90^{\circ}90 ∘ counterclockwise about the origin? (NO BITLY LINKS!!!!

Or "I don't know the answer sorry :(" answers.)

1 answer:

Naya [18.7K]3 years ago

7 0

Answer:

-6,9 I believe

Step-by-step explanation:

Im pretty sure

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Last year mr.peterson had a fence all the way around his garden. he can reuse all of the fence he had around the garden last yea

lakkis [162]

First, you need to find out the perimeter of the fence and how much of the fence he had around his garden last year (leftovers) and subtract them I think.

4 0

3 years ago

I need help with #6 please.

Juliette [100K]

9514 1404 393

Answer:

6. (A, B, C) ≈ (112.4°, 29.5°, 38.0°)

7. (a, b, C) ≈ (180.5, 238.5, 145°)

Step-by-step explanation:

My "work" is to make use of a triangle solver calculator. The results are attached. Triangle solvers are available for phone or tablet and on web sites. Many graphing calculators have triangle solvers built in.

__

We suppose you're to make use of the Law of Sines and the Law of Cosines, as applicable.

6. When 3 sides are given, the Law of Cosines can be used to find the angles. For example, angle A can be found from ...

A = arccos((b² +c² -a²)/(2bc))

A = arccos((8² +10² -15²)/(2·8·10)) = arccos(-61/160) = 112.4°

The other angles can be found by permuting the variables appropriately.

B = arccos((225 +100 -64)/(2·15·10) = arccos(261/300) ≈ 29.5°

The third angle can be found as the supplement to the other two.

C = 180° -112.411° -29.541° = 38.048° ≈ 38.0°

The angles (A, B, C) are about (112.4°, 29.5°, 38.0°).

__

7. When insufficient information is given for the Law of Cosines, the Law of Sines can be useful. It tells us side lengths are proportional to the sine of the opposite angle. With two angles, we can find the third, and with any side length, we can then find the other side lengths.

C = 180° -A -B = 145°

a = c(sin(A)/sin(C)) = 400·sin(15°)/sin(145°) ≈ 180.49

b = c(sin(B)/sin(C)) = 400·sin(20°)/sin(145°) ≈ 238.52

The measures (a, b, C) are about (180.5, 238.5, 145°).

7 0

3 years ago

What is the value of x in the equation below?

belka [17]

$remember$
$ln(a^b)=bln(a)$
$ln(e)=1$
$so$
$ln(e^x)=xln(e)=x$

$1+2e^{x+1}=9$
$minus \space\ 1 \space\ both \space\ sides$
$2e^{x+1}=8$
$divide \space\ both \space\ sides \space\ by \space\ 2$
$e^{x+1}=4$
$take \space\ ln \space\ of \space\ both \space\ sides$
$ln(e^{x+1})=ln(4)$
$(x+1)ln(e)=ln(4)$
$x+1=ln(4)$
$minus \space\ 1 \space\ from \space\ both \space\ sides$
$x=ln(4)-1$
$answer \space\ is \space\ C=ln(4)-1$

5 0

3 years ago

Read 2 more answers

When Harper commutes to work, the amount of time it takes her to arrive is normally distributed with a mean of 24 minutes and a

Korvikt [17]

Answer:

$\mu -2\sigma = 24-2*3= 18$

$\mu -2\sigma = 24+2*3= 30$

So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case

Step-by-step explanation:

For this case we can define the random variable X as the amount of time it takes her to arrive to work and we know that the distribution for X is given by:

$X \sim N(\mu = 24, \sigma =3)$

And we want to use the empirical rule to estimate the middle 95% of her commute times. And the empirical rule states that we have 68% of the values within one deviation from the mean, 95% of the values within two deviations from the mean and 99.7 % of the values within 3 deviations from the mean. And we can find the limits on this way:

$\mu -2\sigma = 24-2*3= 18$

$\mu -2\sigma = 24+2*3= 30$

So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case

7 0

3 years ago

1.) (-18, -20) (18, 16)

aleksandrvk [35]

1.) (-18, -20) (18, 16)

m= 1

2.) (-7, 14) (-11, 4)

m= 5/2

3.) (-5, -4) (3, 9)

m= 13/8

4.) (13, -8) (-9, -1)

m= -7/22

3 0

4 years ago