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sesenic [268]
3 years ago
12

I don’t know, someone help please.

Mathematics
1 answer:
NeTakaya3 years ago
3 0

Answer:

Radius: 4

Center: (-5,4)

Step-by-step explanation:

To find the radius, you take the square root of what the equation is equal to (in this case that is 16)

To find the center, you set what is in the parenthesis equal to 0 so:

x+5=0 becomes x=-5

y-4=0 becomes y=4

Hope this helped!

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I am a 2-digit number. I am a am an even number. The sum of all my digits together is 3. The order of my digits goes smallest to
julia-pushkina [17]

Answer:

12

Step-by-step explanation:

12 = 2 digits

1 + 2 = 3

1 < 2

8 0
3 years ago
Read 2 more answers
What is the solution of the system? Use elimination.<br><br> 3 (-5x-2y=6)<br> 3x+6y=6
Iteru [2.4K]

Answer:

x = -2 and y = 2

Step-by-step explanation:

The given equations are :

-5x-2y=6 ...(1)

3x+6y=6 ...(2)

Multiply equation (1) by 3. SO,

-15x-6y=18 ...(3)

Adding equation (2) and (3).

3x+6y-15x-6y = 6+18

-12x = 24

x = -2

Put the value of x in equation (1).

-5(-2)-2y=6

10-2y=6

4=2y

y = 2

So, the value of x is -2 and y is 2.

6 0
2 years ago
What is the volume, in cubic inches, of a cylinder with a height of 16 inches and a base radius of 3 inches
icang [17]

Answer:

452.39 would be the volume

Step-by-step explanation:

V = π r² h

3.14 x 9 x 16

6 0
3 years ago
Gravel is being dumped from a conveyor belt at a rate of 10 cubic feet per minute. It forms a pile in the shape of a right circu
Sunny_sXe [5.5K]

Answer:

0.0221 feet per minute.

Step-by-step explanation:

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

Rate of Change of the Volume, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Since gravel is being dumped from a conveyor belt at a rate of 10 cubic feet per minute. Therefore, the Volume of the cone is increasing at a rate of 10 cubic feet per minute.

\dfrac{dV}{dt}=10$ ft^3/min

We want to determine how fast is the height of the pile is increasing when the pile is 24 feet high.

We have:

\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10\\\\$When h=24$ feet$\\\dfrac{3\pi *24^2}{12}\dfrac{dh}{dt}=10\\144\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{144\pi}\\ \dfrac{dh}{dt}=0.0221$ feet per minute

When the pile is 24 feet high, the height of the pile is increasing at a rate of 0.0221 feet per minute.

4 0
3 years ago
The domain for f(x) and g(x) is the set of all real numbers.
Tom [10]

Answer:

Option B

Step-by-step explanation:

=> f(x) = 3x+5

=> g(x) = x^2

Subtracting both

=> (f-g)(x) = 3x+5-x^2

Assembling

=> (f-g)(x) = -x^2+3x+5

3 0
2 years ago
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