Asa saves dimes and quarters so that he will have exact change for he bus. He dabs and then dumps the container that he has been

Question

3 years ago

6

using for collecting his coins and finds he has 47 coins that are worth $9.50. How many of each coin does he have?

1 answer:

koban [17] · Answer 1 · 2022-01-17T07:32:37+03:00

Asa has 15 dimes and 32 quarters.

Step-by-step explanation:

Given,

Total coins = 47

Worth of coins = $9.50 = 9.50*100 = 950 cents

1 dime = 10 cents

1 quarter = 25 cents

Let,

Number of dimes = x

Number of quarters = y

According to given statement;

x+y=47 Eqn 1

10x+25y=950 Eqn 2

Multiplying Eqn 1 by 10

$10(x+y=47)\\10x+10y=470\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(10x+25y)-(10x+10y)=950-470\\10x+25y-10x-10y=480\\15y=480$

Dividing both sides by 15

$\frac{15y}{15}=\frac{480}{15}\\y=32$

Putting y=32 in Eqn 1

$x+32=47\\x=47-32\\x=15$

Asa has 15 dimes and 32 quarters.

Keywords: linear equation, elimination method

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