Answer:
![\left[\begin{array}{cc}x&y&-2&-9&0&-1&2&7&4&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%26-2%26-9%260%26-1%262%267%264%2615%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given

Required
Create a function table for inputs -2, 0, 2 and 4
When x = -2

When x = 0

When x = 2

When x = 4

So, the table is:
![\left[\begin{array}{cc}x&y&-2&-9&0&-1&2&7&4&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%26-2%26-9%260%26-1%262%267%264%2615%5Cend%7Barray%7D%5Cright%5D)
Answer:
2l + 2w. l+l+w+w. l+l+2w. 2(l+w)
Answer:
Kayla should mark the level 3 whole tick marks to the left of the zero on the number line.
Step-by-step explanation:
This would mean the number is negative, for it is on the left of the zero. Another way to say this could be that the absolute value of -3 is three, for it is three whole tick marks from the zero.
is the slash supposed to be division or a fraction?
Answer:
2 should be distributed as 2y + 16; y = 8
Step-by-step explanation:
We have to distribute 2, then:
Now we have to sum (-2y) in both sides of the equation:
Finally we have to divide both sides of the equation in 2:
Then the answer is 2 should be distributed as 2y + 16; y = 8
Hope this helps.