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3 years ago

12

How does the geography of healthy influence population dynamics

Advanced Placement (AP)

1 answer:

ddd [48]3 years ago

4 0

Answer:

The physical health of the mother being a key factor. In societies where most women bear a large number of babies, the women also tend to be inadequately nourished, exhausted from over work, suffering from disease, and poor educated.

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Andy's two nephews want to travel to Philadelphia with him to see a show. Andy has two free plane tickets and three tickets to t

qaws [65]

I believe it is a scarce resource because they are 1 ticket short.

5 0

3 years ago

When was another time sedition acts were passed

Helga [31]

Sedition act (of 1798) signed into law by president adams, and sedition act of 1918 that extended the espionage act of 1917

sorry if this is not the answer you needed

3 0

3 years ago

1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

a.

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

b.

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

c.

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

d.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

8 0

1 year ago

PLS HELP ME with this <br><br>only PILLIPINES can understand this

pickupchik [31]

Answer

I’m not philippine so I can’t help lol

4 0

2 years ago

With a half life of 28.8 years, how long will it take 1g of strontium-90 to decay to 250 mg

soldier1979 [14.2K]

The time it takes for 1g of strontium-90 to decay to 250 mg is; 57.6 years

<h3>What is the half life of an element?</h3>

The formula for half life is;

A(t) = A₀ * (¹/₂)^(t/t_1/2)

Where;

A(t) is amount left after t years

A₀ the initial quantity of the substance that will undergo decay;

t_1/2 is the half-life of the decaying quantity.

We are given;

t_1/2 = 28.8 years

A₀ = 1 g

A(t) = 250 mg = 0.25 g

Thus;

0.25 = 1 * (¹/₂)^(t/28.8)

log 0.25 = (t/28.8) log (1/2)

-0.60206 = (t/28.8) * -0.3010

t = 2 * 28.8

t = 57.6 years

Read more about half life at; brainly.com/question/11152793

6 0

2 years ago