Answer:
The answer to this question is 19.
Step-by-step explanation:
Given that :
f(x)=13.
f'(x)=3. 1 ≤ x ≤ 3.
Integrate
∫f'(x) dx=∫3 dx
f(x)=3x+c 1 ≤ x ≤ 3.
f(1)= 3+c
c=13-3 =10.
f(x)=3x+10 1 ≤ x ≤ 3.
now ,
f(3)=3(3)+10=19.
So f(3) is at least 19.
1/2x-2/5=3/5 (BTW I got 2/5 by reducing 4/10)
1/2x=7/5 (BTW I got 7/5 by moving 2/5 to the other side)
Then do 7/5 times 2 and you get 14/5
14/5
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Answer:
type 2 in the first box,
13/4 in the second box, and
-9/8 in the third one
Step-by-step explanation:Notice that you are asked to write the following quadratic expression in vertex form, so you need to find the "x" value of the vertex, and then the "y" value of the vertex:
Which in our case is: -13/4
and the value of the y for the vertex is obtained using the functional expression when x equals -13/4:
Then your expression for this quadratic should be:
Then type 2 in the first box, 13/4 in the second box, and -9/8 in the third one
Answer:
Step-by-step explanation:
X no of questions student answers is binomial with n =40 and p =0.5
If approximated to normal, X is Normal with
mean = np = 20 and variance = npq = 10
P(X>N) >0.10
We use std normal distribution table to get z value first then convert to x value
So 
This is with continuity correction.
Hence without continuity correction this equals 7.2-0.5 = 6.7
x>6.7
n = 7
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y = 7x - 4x²
<span>7x - 4x² = 0 </span>
<span>x(7 - 4x) = 0 </span>
<span>x = 0, 7/4 </span>
<span>Find the area of the bounded region... </span>
<span>A = ∫ 7x - 4x² dx |(0 to 7/4) </span>
<span>A = 7/2 x² - 4/3 x³ |(0 to 7/4) </span>
<span>A = 7/2(7/4)² - 4/3(7/4)³ - 0 = 3.573 </span>
<span>Half of this area is 1.786, now set up an integral that is equal to this area but bounded by the parabola and the line going through the origin... </span>
<span>y = mx + c </span>
<span>c = 0 since it goes through the origin </span>
<span>The point where the line intersects the parabola we shall call (a, b) </span>
<span>y = mx ===> b = m(a) </span>
<span>Slope = m = b/a </span>
<span>Now we need to integrate from 0 to a to find the area bounded by the parabola and the line... </span>
<span>1.786 = ∫ 7x - 4x² - (b/a)x dx |(0 to a) </span>
<span>1.786 = (7/2)x² - (4/3)x³ - (b/2a)x² |(0 to a) </span>
<span>1.786 = (7/2)a² - (4/3)a³ - (b/2a)a² - 0 </span>
<span>1.786 = (7/2)a² - (4/3)a³ - b(a/2) </span>
<span>Remember that (a, b) is also a point on the parabola so y = 7x - 4x² ==> b = 7a - 4a² </span>
<span>Substitute... </span>
<span>1.786 = (7/2)a² - (4/3)a³ - (7a - 4a²)(a/2) </span>
<span>1.786 = (7/2)a² - (4/3)a³ - (7/2)a² + 2a³ </span>
<span>(2/3)a³ = 1.786 </span>
<span>a = ∛[(3/2)(1.786)] </span>
<span>a = 1.39 </span>
<span>b = 7(1.39) - 4(1.39)² = 2.00 </span>
<span>Slope = m = b/a = 2.00 / 1.39 = 1.44</span>
