Solve for x. 3x - 8x + 2 = 17 X=

Instructions: Perform the given operation for the two stated functions. Type your answer in the space given. Remember to use the

andriy [413]

Answer:

-1 because when you add both functions thats what you get.

3 0

3 years ago

Find the distance between the point (-2, -3) and the line with the equation y=4-2/3x

otez555 [7]

Answer:

$D = \frac{25\sqrt{13}}{13}$

Step-by-step explanation:

Given

$y = 4 - \frac{2}{3}x$

$(x_1,y_1) = (-2,-3)$

Required

Determine the distance

$y = 4 - \frac{2}{3}x$

Write the above equation in standard form:

$Ax + By + C = 0$

So, we have:

$\frac{2}{3}x+y - 4 = 0$

By comparison:

$A = \frac{2}{3}$ $B = 1$ and $C = -4$

The distance is calculated using:

$D = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}$

Where:

$(x_1,y_1) = (-2,-3)$

$A = \frac{2}{3}$ $B = 1$ and $C = -4$

This gives:

$D = \frac{|\frac{2}{3} * (-2) + 1 * (-3) - 4|}{\sqrt{(\frac{2}{3})^2 + 1^2}}$

$D = \frac{|-\frac{4}{3} -3 - 4|}{\sqrt{\frac{4}{9} + 1}}$

Take LCM

$D = \frac{|\frac{-4-9-12}{3}|}{\sqrt{\frac{4+9}{9}}}$

$D = \frac{|\frac{-25}{3}|}{\sqrt{\frac{13}{9}}}$

$D = |\frac{-25}{3}|/\sqrt{\frac{13}{9}}$

$D = \frac{25}{3}/\sqrt{\frac{13}{9}}$

Split the square root

$D = \frac{25}{3}/\frac{\sqrt{13}}{\sqrt{9}}$

Change / to *

$D = \frac{25}{3}*\frac{\sqrt{9}}{\sqrt{13}}$

$D = \frac{25}{3}*\frac{3}{\sqrt{13}}$

$D = \frac{25}{\sqrt{13}}$

Rationalize

$D = \frac{25}{\sqrt{13}} * \frac{\sqrt{13}}{\sqrt{13}}$

$D = \frac{25\sqrt{13}}{13}$

Hence, the distance is:

$D = \frac{25\sqrt{13}}{13}$

4 0

3 years ago

In Triangle XYZ, A is the midpoint of XY, B is the midpoint of YZ, and C is the midpoint of XZ.

Roman55 [17]

The perimeter of triangle ABC is 24 units

Step-by-step explanation:

If a segment joining the mid points of two sides of a triangle, then

this segment is:

Parallel to the third side
Its length is half the length of the third side

In The triangle XYZ

∵ A is the mid point of XY

∵ B is the mid point of YZ

∴ AB = $\frac{1}{2}$ XZ

∵ XZ = 18 units

- Substitute the value of XZ in AB

∴ AB = $\frac{1}{2}$ × 18 = 9 units

∵ B is the mid point of YZ

∵ C is the mid point of XZ

∴ BC = $\frac{1}{2}$ XY

∵ AY = 7 units

∵ AY = $\frac{1}{2}$ XY

∴ XY = 2 × AY

∴ XY = 2 × 7

∴ XY = 14 units

∴ BC = $\frac{1}{2}$ × 14 = 7 units

∵ A is the mid point of XY

∵ C is the mid point of XZ

∴ AC = $\frac{1}{2}$ YZ

∵ BZ = 8 units

∵ BZ = $\frac{1}{2}$ YZ

∴ YZ = 2 × BZ

∴ YZ = 2 × 8

∴ YZ = 16 units

∴ AC = $\frac{1}{2}$ × 16 = 8 units

∵ The perimeter of a triangle = the sum of the lengths of its sides

∴ Perimeter Δ ABC = AB + BC + AC

∴ Perimeter Δ ABC = 9 + 7 + 8 = 24 units

The perimeter of triangle ABC is 24 units

Learn more:

You can learn more about triangles in brainly.com/question/5924921

#LearnwithBrainly

5 0

3 years ago

Rewrite the equation by completing the square. x^2 - 4x + 3 = 0

Degger [83]

Answer:

the answer would be x=3,1

4 0

3 years ago

Read 2 more answers

2/5 + 3/8 - Adding fractions

m_a_m_a [10]

Answer:31/40

Step-by-step explanation:

To add you have to have a common denominator. To get that you can multiply each fraction by one in different ways. 2/5 *8/8= 16/40 and 3/8* 5/5= 15/40 and then add those two to give you 31/40.

5 0

3 years ago

Read 2 more answers