To find the value of f(3) we need to follow the below steps :
Step 1 : First plot the graph of f(x)
Step 2 : We need to find f(3) or the function value at x = 3 therefore, in the graph locate the point (3,0)
Step 3 : Draw a line parallel to Y-axis passing through the point (3,0) .
Step 4 : Now there exists two cases :
If the drawn line do not intersect the graph of f(x), then no value of f(3) exists for the given function of x
If the drawn line intersects the graph, then the intersection point is marked and a line parallel to x - axis is drawn passing through that marked or intersection point. And the line where it intersects the y - axis is our required value of f(3).
If this is wrong than I guess I wasn't smart enough :)
Answer:
The Answer is 76.
Step-by-step explanation:
Given the normal distribution " 10% of employees (rated) exemplary, 20% distinguished, 40% competent, 20% marginal, and 10% unacceptable'', we can see that exemplary employees are top 10% rated employees.
We have the formula for normal distribution:
z=(X-M)÷σ
where z is the <em>minimum z-score </em>for top 10% employee, X is the <em>minimum </em>score for top 10% employee, M is the <em>mean</em> of the score distribution, σ is the <em>standard deviation</em> of the score distribution.
The z-score we are looking for is the value "a" that separates the highest 10% from the lowest 90% i.e. P(z≤a)=0.90
If we look at z-table, corresponding value for a is 1.28155
We can now put the values in the formula:
1.28155=
So X=(1.28155×20)+50=75.631
Therefore minimum score for exemplary employee is 76.
Answer:
the answer is 17.3 repeated
Step-by-step explanation:
because 52 divided by 3