3 > 1
(4^0 is one)
3 is greater than 4^0
Pretty simple.
First term (a) = -15
common difference(d)= -9-(-15)
= -9+15=6
So,
12th term(a12)= a +(n-1)d
= -15+(12-1)×6
= -15 + 11×6
= -15+66
= 51
Answer:
7. 49
8. 10.4
Step-by-step explanation:
7) our hypotenuse is 8, and the side opposite the base of ladder and ground angle is 6, therefore we can use Sin
sin = opposite/hypotenuse
sin(x) = 6/8 = 3/4
sin-1(3/4) = 49
8) using the theorem that alternate exterior angles are congruent
the angle opposite side x is 30
tan = opposite/adjacent
tan(30) = x/18
x = 18tan(30) = 6√(3) = 10.4
you can also use 30-60-90 special right triangles.
the side opposite 30 is x
side opposite 60 is x√(3)
and side opposite 90 is 2x
Answer:
x=28+n
Step-by-step explanation:
So, the teacher is giving Jonathan papers so we know its addition.
28+n
So lets have x equal the amount of papers he has on his desk after the new papers are added.
x=28+n
1. 0
2. 32.6
3. 326
4. 3260
considering i’m not the best at maths, can someone check these for me?
