I think I get 2 and 4, for that one. I think you are supposed to make up an equation, such as xy ≤ x²
Answer:
x1=-1, x2=4/5
Step by step explanation:
5x^2 - 4 + x = 0
Use the commutative property to reorder the terms:
5x^2+x-4=0
Write x as a difference:
5x^2+5x-4x-4=0
Factor out 5x from the expression:
5xx(x-1)-4x - 4=0
Factor out -4 from the expression:
5xx(x+1) - 4 (x-1)=0
Factor out x+1 from the expression:
(x-1) x (5x-4) =0
When the product of factors equal 0 at least one factor is 0
X + 1 = 0
5x - 4 = 0
Solve the equation:
The equation has two solutions
X1=-1, x2 = 4/5
Answer:a. 2 b. 5/3 c. 3/2 d. 1 e. 1/2 already in order from greatest to least. in rate order of least to greatest e,d,c,b,a
Step-by-step explanation: linear equation formula is y=mx+b. M represents the slope or rate of change.
Answer:
0.0167
Step-by-step explanation:
There are 5 "Sig Figs" in this number: 1, 6, 6, 6, and 7
0.01666 rounded to <em>three</em> significant figures is .0167.
Answer:
The solutions for the given system of equations are:
Step-by-step explanation:
Given the equation system:
We obtain the following matrix:
![\left[\begin{array}{cccc}3&1&4&-3\\-1&1&4&17\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%261%264%26-3%5C%5C-1%261%264%2617%5Cend%7Barray%7D%5Cright%5D)
<u>Step 1:</u> Multiply the fisrt row by 1/3.
![\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\-1&1&4&17\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%26%5Cfrac%7B1%7D%7B3%7D%20%26%5Cfrac%7B4%7D%7B3%7D%26-1%5C%5C-1%261%264%2617%5Cend%7Barray%7D%5Cright%5D)
<u>Step 2:</u> Sum the first row and the second row.
![\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&\frac{4}{3} &\frac{16}{3}&16\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%26%5Cfrac%7B1%7D%7B3%7D%20%26%5Cfrac%7B4%7D%7B3%7D%26-1%5C%5C0%26%5Cfrac%7B4%7D%7B3%7D%20%26%5Cfrac%7B16%7D%7B3%7D%2616%5Cend%7Barray%7D%5Cright%5D)
<u>Step 3:</u> Multiply the second row by 3/4.
![\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&1 &4&12\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%26%5Cfrac%7B1%7D%7B3%7D%20%26%5Cfrac%7B4%7D%7B3%7D%26-1%5C%5C0%261%20%264%2612%5Cend%7Barray%7D%5Cright%5D)
<u>Step 4:</u> Multiply the second row by -1/3 and sum the the first row.
![\left[\begin{array}{cccc}1&0 &0&-5\\0&1 &4&12\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%20%260%26-5%5C%5C0%261%20%264%2612%5Cend%7Barray%7D%5Cright%5D)
The result of the reduced matrix is:
This is equal to:
These are the solutions for the system of equations in terms of z, where z can be any number.
