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myrzilka [38]
3 years ago
13

Chegg A full bootstrap program Select one: a. may be infected by viruses. b. is stored in ROM to ensure to avoid any infection f

rom viruses. NOT c. is part of an operating system
Computers and Technology
1 answer:
harina [27]3 years ago
8 0

Answer:

Option b = "is stored in ROM to ensure to avoid any infection from viruses. "

Explanation:

In order to to understand the fundamentals of an Operating system in computer one needs to know what the bootstrap program is.

The BOOTSTRAP PROGRAM is first program that will run when the computer is switched on, thus the program( the BOOTSTRAP PROGRAM) will be the program to open the OPERATING SYSTEM.

The device in laptops and personal computers known as ROM is an acronym that stands for Read-Only Memory and it is a storage medium. Because of ROM inability to get Virus it is used in the storage of Bootstrap program.

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Program MATH_SCORES: Your math instructor gives three tests worth 50 points each. You can drop one of the test scores. The final
Simora [160]

Answer:

import java.util.Scanner;

public class num5 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       //Prompt and receive the three Scores

       int score1;

       int score2;

       int score3;

       do {

           System.out.println("Enter first Score Enter score between 1 -50");

           score1 = in.nextInt();

       } while(score1>50 || score1<0);

       do {

           System.out.println("Enter second Score.The second score must be between 1 -50");

           score2 = in.nextInt();

       } while(score2>50 || score2<0);

       do {

           System.out.println("Enter Third Score Third score must between 1 -50");

           score3 = in.nextInt();

       } while(score3>50 || score3<0);

       //Find the minimum of the three to drop

       int min, min2, max;

       if(score1<score2 && score1<score3){

           min = score1;

           min2 = score2;

           max = score3;

       }

       else if(score2 < score1 && score2<score3){

           min = score2;

           min2 = score1;

           max = score3;

       }

       else{

           min = score3;

           min2 = score1;

           max = score2;

       }

       System.out.println("your entered "+max+", "+min2+" and "+min+" the min is");

       int total = max+min2;

       System.out.println("Total of the two highest is "+total);

       //Finding the grade based on the cut-off points given

       if(total>=90){

           System.out.println("Grade is A");

       }

       else if(total>=80){

           System.out.println("Grade is B");

       }

       else if(total>=70){

           System.out.println("Grade is C");

       }

       else if(total>=60){

           System.out.println("Grade is D");

       }

       else{

           System.out.println("Grade is F");

       }

   }

}

Explanation:

  • Implemented with Java
  • Use the scanner class to receive user input
  • Use a do.....while loop to validate user input for each of the variables. A valid score must be between 0 and 50 while(score>50 || score<0);  
  • Use if and else to find the minimum of the three values and drop
  • Add the two highest numbers
  • use if/else if /else statements to print the corresponding grade
8 0
3 years ago
Types of lines in dressmaking
Shtirlitz [24]

Answer:

table of contents/ straight line/horizontal line/diagonal line/zigzag line/curved line(softly)  curved line(fully)  thin line

Explanation:

your welcome

5 0
4 years ago
Which ipsec subprotocol provides data encryption?
Mrac [35]
I'm not sure but I think LastPass?
6 0
4 years ago
Please help
zvonat [6]

Answer:

First check the if the adapters on the router or site are connected (Ipconfig)

Next run a flush Dns to clear the sites dns logs (ipconfig/flushdns)

If non of that works you would run a restart on the server that is transfering data through the site.

If that doesn't work you will have to call a tech support from another company or your boss to tell him that there is nothing you can do and to ask for help!

Explanation:

Hopefully this helps! BTW I'm 13 so I wouldn't rely on my information that is personal what I would do though.

6 0
3 years ago
You are auditing a client's network and have gained physical access to a workstation. To prevent any security software from dete
Llana [10]

Answer:

OphCrack LiveCD.

Explanation:

The user examines that server of a client, as well as requires complete control of such a system. To avoid recognizing its invasion by certain security programs, he wants to select a LiveCD which can break Operating System's credentials,  and he would have been using OphCrack LiveCD because it used to crack the credential of the Windows user.

So, the following are the reason by which the answer is correct according to the scenario.

3 0
3 years ago
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