Answer:
an error message
Explanation:
The return value is the value which is sent back by the function to a place in the code from where the 
was called from. Its main work is to return a value form the function.
In the context, the form of "(symbol-length? 'James)" in Scheme will return the value --- ' an error message'.
Answer:
Following is the code for filter:
public class filter
{ public static void main(String[] args)
{ int x = StdIn.readInt();
System.out.print(" " + x + " ");
while(!StdIn.isEmpty())
{ int y = StdIn.readInt();
if(y != x)
System.out.print(" " + y + " ");
x = y;
}
}
}
Explanation:
- A public class filter is used.
- The main function will accept a single argument as string[], it is also known as java command line argument.
- Now the Stdln.readInt is used to read the integers in the sequence and store it in integer x.
- The value stored in variable x will be printed using System.out.print
- Now unless the Stdln.readInt gets an empty value, check each value of sequence and store in variable y.
- If y is not equal to previous value x, print it and shift the value of y into x.
- Repeat the loop again.
i hope it will help you!
Answer:
Option A: print("The total is %0.5f" % total)
Explanation:
To ensure the value is rounded to a precision of 5 digits, we have to create a formatted string which is %0.5f. The <em>.5</em> denotes five decimal places and <em>f </em>refers to float data type.
Next, we use the <em>%</em> operator again and followed with the variable <em>total</em>. The % is used as a string modulo operator that will interpolate the value held by the the variable <em>total </em>in the formatted string that we create previously. The interpolated value will be rounded to 5 decimal places. For example, if
total = 256.786789
The output will be 256.78679
Answer:
/*
I don't know what language you're using, so I'll write it in javascript which is usually legible enough.
*/
console.log(buildSequence(30));
function buildSequence(maxVal){
maxVal = Math.abs(maxVal);
var n, list = [];
for(n = 1; n < maxVal; n++){
/*
to check for odd numbers, we only need to know if the last bit
is a 1 or 0:
*/
if(n & 1){ // <-- note the binary &, as opposed to the logical &&
list[list.length] = n;
}else{
list[list.length] = -n;
}
}
return list.implode(',');
}
Both yeah and no, depending on personal opinion
