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3 years ago

There are 18 fish in a 1 ft x 4 ft x 7 ft fish tank. What is the population density in the fish tank?

Mathematics

2 answers:

stealth61 [152]3 years ago

8 0

Find the volume of the tank:

Volume = 1 x 4 x7 = 28 cubic feet.

Divide number of fish by volume:

18/28 = 9/14 fish per cubic foot.

MakcuM [25]3 years ago

6 0

Answer:

0.643 fish / cubic foot to the nearest thousandth.

Step-by-step explanation:

The volume of the tank = 1 * 4 * 7

= 28 ft^3.

The population density = the number of fish / the volume of the water

= 18/28

= 0.643.

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lutik1710 [3]

Answer:

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Step-by-step explanation:

-9 + x = 5x - 7

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3 years ago

After breaking your penny bank, you notice that you have $4.87 in quarters ($0.25), dimes ($0.10), nickels ($0.05), and pennies

ira [324]

Answer: Option 'c' is correct.

Step-by-step explanation:

Let the number of dimes be 'x'.

Let the number of nickels be ' $\dfrac{3}{2}x$ '.

Let the number of pennies be $\dfrac{3}{2}\times 2x=3x$

Let the number of quarters be '3x-34'.

As we know that

1 quarter = $0.25

1 dime = $0.10

1 nickel = $0.05

1 penny = $0.01

According to question, we get that

$0.10x+0.05\times \dfrac{3x}{2}+0.01\times 3x+0.25(3x-34)=4.87\\\\0.10x+0.075x+0.03x+0.75x-8.5=4.87\\\\\\0.955x=4.87+8.5\\\\0.955x=13.37\\\\x=\dfrac{13.37}{0.955}\\\\x=14$

So, the number of pennies is given by

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Hence, Option 'c' is correct.

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Marat540 [252]

Answer:

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Putting w = 16
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Step-by-step explanation:

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