the cost of 6 sandwiches and 4 drinks is $53. the cost of 4 sandwiches and 6 drinks is #47. how much does one sandwich cost?
1 answer:
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Answer: - 49
Step-by-step explanation:
f(x) = -2x - 1
g(x) = - 1
fg(x) = f ( - 1) , we just put in the value of g(x) , the next thing is to substitute
- 1 for the value of x in f(x) , that is
fg(x) = -2( - 1) - 1
fg(x) = -2 + 2 - 1
fg(x) = -2 + 1
Therefore : fg(-5) means we will substitute -5 for x in fg(x) , that is
fg(-5) = -2 ( + 1
fg(-5) = -2(25) + 1
fg(-5) = -50 + 1
fg(-5) = -49
Answer:
x = - 1 ± 2i
Step-by-step explanation:
we can use the discriminant b² - 4ac to determine the nature of the roots
• If b² - 4ac > , roots are real and distinct
• If b² - 4ac = 0, roots are real and equal
• If b² - ac < 0, roots are not real
for x² + 2x + 5 = 0
with a = 1, b = 2 and c = 5, then
b² - 4ac = 2² - (4 × 1 × 5 ) = 4 - 20 = - 16
since b² - 4ac < 0 there are 2 complex roots
using the quadratic formula to calculate the roots
x = ( - 2 ± ) / 2
= (- 2 ± 4i ) / 2 = - 1 ± 2i
Answer:
Cost price of each candy = $0.80, Selling price of each candy = $1.40
Step-by-step explanation:
Given:
Ramiro buys 50 packs of candy bars for $40 before a tax of 7.5%.
He sells each candy var for 175% of what he paid before tax.
Question asked:
How much does he buy each candy bar for ?
How much does he sell one for ?
Solution:
<u>By unitary method:</u>
Cost of 50 packs of candy bars = $40
Cost price of 1 pack of candy bars =
Cost price of each candy = $0.80
Thus, he buy each candy bar for $0.80
Now:-
As he sells each candy var for 175% of what he paid before tax:-
Selling price of each candy = 0.80 175%
=
Thus, he sell one candy for $1.40