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2 years ago

Solve: 7-5x= -5x - 6x +7

Mathematics

2 answers:

olga2289 [7]2 years ago

8 0

Answer:

actually it is x=0

Step-by-step explanation:

docker41 [41]2 years ago

6 0

7=-16x+7
0=-16x
0=x

7-0=0-0+7
7=7

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Find the missing factor B that makes the equality true. 21y^4= (B) (7y^3)

adelina 88 [10]

Answer:

21y^4= B*7y^3

B=(21y^4)/(7y^3)

B=3y

8 0

2 years ago

PLEASE HELP ME I BEGGGGGGG

Hoochie [10]

Answer:

Step-by-step explanation:

6 0

2 years ago

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During the exponential phase, E. coli bacteria in a culture increase in number at a rate proportional to the current population.

NikAS [45]

Answer:

197.2 million

Step-by-step explanation:

The appropriate exponential equation for the population is ...

p(t) = 172.0e^(0.019t)

Then we can compute for t=7.2:

p(7.2) = 172.0e^(0.019·7.2) ≈ 172.0·1.146599 ≈ 197.2

7.2 minutes from now, the population will be about 197.2 million.

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For continuous growth (or continuous compounding), the exponential formula is ...

f(t) = (value at t=0)×e^(rt)

where r is the growth rate in one unit of time, and t is the number of time periods.

8 0

3 years ago

What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)

UkoKoshka [18]

Answer:

$\boxed{m = - \frac{33}{14} }$

Step-by-step explanation:

Use the form below

$\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}$

Where

$m$ is a slope
$(x_1,~y_1)$ and $(x_2,~y_2)$ are the point of the line

So, the slope is

$(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1$

$(-2,~ \frac{9}{2} ) \to x_2 = -2~and~y_2 = \frac{9}{2}$

$m = \frac{\frac{9}{2} -(-1)}{-2-\frac{1}{3} }$

$m = \frac{\frac{11}{2} }{\frac{-7}{3} }$

$m = \frac{11}{2} \div (-\frac{7}{3} )$

$m = \frac{11}{2} \times (-\frac{3}{7} )$

$m = - \frac{33}{14}$

Happy to help:)

7 0

3 years ago

Read 2 more answers

1) State the amplitude, period, phase shift, vertical shift and graph

bogdanovich [222]

Answer:

See answers and explanations below (along with a visual graph)

Step-by-step explanation:

For the function $y=acos(b(x+c))+d$ :

Amplitude: $|a|$

Period: $\frac{2\pi}{|b|}$

Phase shift: $\frac{-c}{b}$

Vertical shift: $d$

Therefore, for $y=2cos(\frac{2}{3}(\theta+\pi))-1$ :

Amplitude: $|a|=|2|=2$ , which is 2 units above and below the midline (see d)

Period: $\frac{2\pi}{|b|}=\frac{2\pi}{|\frac{2}{3}|}=\frac{2\pi}{\frac{2}{3}}=3\pi$ , so the cycle will repeat every 3π units

Phase shift: $\frac{-c}{b}=\frac{-\frac{2\pi}{3} }{\frac{2}{3} }=-\pi$ , or π units to the left

Vertical shift: $d=-1$ , or 1 unit down

3 0

2 years ago