The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
The answer is D.
You have to make the whole numbers equal to then solve for the exponents:
F(x) means y, therefore, y is 9.
9 = 3^x.
3^2 is the same as 9.
Then, 3^2 = 3^x.
Then solve for the exponents,
2 = x
Therefore your answer is 2.
Answer:
x2 = -0.600000
x3 = -0.521600
Step-by-step explanation:
Given the formula;
xn+1 = (xn)³-5/10
x2 = (x1)³-5/10
Given x1 = -1
x2 = (-1)³-5/10
x2 = (-1-5)/10
x2 = -6/10
x2 = -0.600000
x3 = (x3)³-5/10
Given x3 = -0.6
x3 = (-0.6)³-5/10
x3 = (-0.216-5)/10
x3 = -5.216/10
x3 = -0.521600
Answer:
c i think
Step-by-step explanation: