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3 years ago

10

you deposit 1,750 into an interestmemt account that will produce 6.05% annual interest the money was left in the account for 2 y

ear how much interest has accured after 2 years

1 answer:

Ymorist [56]3 years ago

5 0

Answer:

i dont know mabey someone else knows

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zmey [24]

Answer:

Computers R Us has a better price because it cost less at the same production rate.

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3 years ago

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Solve these equations. Thanks.

Nutka1998 [239]

Answer:

1. 3.572 x 10^(-1)

2. 3.108 x 10^(6)

3. 5.31881533 x 10^(-6)

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3 years ago

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc

Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when $M = 0.3, \sigma = 4.103$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.3 = 1.96*\frac{4.103}{\sqrt{n}}$

$0.3\sqrt{n} = 1.96*4.103$

$\sqrt{n} = \frac{1.96*4.103}{0.3}$

$(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}$

$n = 718.57$

Rouding up

We need a sample size of at least 719

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3 years ago

Which of the following tables represents a function? (PLEASE HELP!)

frez [133]

Last one is your answer.
X cannot be repeated, but y can

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