If the mower is pulled over a flat horizontal surface, then first get the component of the force in the direction of the mower's displacement:
(120 N) cos(30°) = 60 √3 N ≈ 103.923 N
Then the work done by the boy on the mower over a distance of 12.8 m is
(103.923 N) (12.8 m) ≈ 1330.2 Nm ≈ 1330 J
Answer:

Step-by-step explanation:
The x intercepts are basically the points at which y = 0.
-x^2 + 2 = 0
-x^2 = -2
x^2 = 2
x = 