Answer:
5, 9, 13, 17, 21, .....
Step-by-step explanation:
To generate the sequence, substitute n = 1, 2, 3, 4, ..... into the rule
a₁ = 4(1) + 1 = 4 + 1 = 5
a₂ = 4(2) + 1 = 8 + 1 = 9
a₃ = 4(3) + 1 = 12 + 1 = 13
a₄ = 4(4) + 1 = 16 + 1 = 17
a₅ = 4(5) + 1 = 20 + 1 = 21
Answer:
The answer in the procedure
Step-by-step explanation:
Let
A1 ------> the area of the first square painting
A2 ----> the area of the second square painting
D -----> the difference of the areas
we have
case 1) The area of the second square painting is greater than the area of the first square painting
The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting
D=A2-A1
case 2) The area of the first square painting is greater than the area of the second square painting
The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting
D=A1-A2
The third side must be >2 and < 18
To test if a triangle is acute, right or obtuse:
1) Square all 3 sides
2) Sum the squares of the 2 shortest sides
3) Compare this sum to side 3 squared
if sum > side 3 squared it is an acute triangle
if sum = side 3 squared it is a right triangle
if sum < side 3 squared it is an obtuse triangle
The shortest side 2 can be is "less than 2" so we'll say it is 2.00000001
three sides squared =
<span>
<span>
<span>
4.00000004
</span>
</span>
</span>
64
100
Summing the 2 shortest sides 4.00000004 + 64 = <span>68.00000004
</span><span>68.00000004 is less than 100 so it is an obtuse triangle no matter how long the third side is.
</span>
Answer:
everyone gets 5 pieces and the rest gets thrown out
Step-by-step explanation:
29/5=5.8
but obviously ur not gonna break the candy into .8 so everyone just gets 5 so its even
The answer is 2
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