Create a function rule for the following:<br><br> x 0 3 6<br> f(x) -5 -3 -1<br> lmk asapppp please

Determining Whether a Difference Is Statistically

SCORPION-xisa [38]

Using the z-distribution, it is found that:

The 95% confidence interval is of -1.38 to 1.38.

The value of the sample mean difference is of 1.74, which falls outside the 95% confidence interval.

<h3>What is the z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm zs$

In which:

$\overline{x}$ is the difference between the population means.

s is the standard error.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The estimate and the standard error are given by:

$\overline{x} = 0, s = 0.69$

Hence the bounds of the interval are given by:

$\overline{x} - zs = 0 - 1.96(0.69) = -1.38$

$\overline{x} + zs = 0 + 1.96(0.69) = 1.38$

1.74 is outside the interval, hence:

The 95% confidence interval is of -1.38 to 1.38.

The value of the sample mean difference is of 1.74, which falls outside the 95% confidence interval.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ2

6 0

2 years ago

Three years ago the average price of a movie ticket was $8.75 and now it is $11.00. What was the annual multiplier and the perce

Andrei [34K]

Given:
Price of tickets:
3 years ago - 8.75
now - 11

annual multiplier:

b³ = 11/8.75
b = ∛11/8.75
b = 1.079

The annual multiplier is 1.079.

1.079 * 100% = 107.9%

107.9% - 100% = 7.9%

The percentage increase is 7.9%

8 0

3 years ago

Describe the difference between parallel and perpendicular lines, their slopes and graphs

Aloiza [94]

Parallel lines have the same slopes (but different y intercepts). Parallel lines never cross. Parallel lines are the same distance from each other no matter where you are on either line. Think of it like a pair of perfectly straight railroad tracks.

-------------------------------------------------------------------------------------

Perpendicular lines cross at one point. The two lines form a 90 degree angle. The two slopes multiply to -1, which is another way of saying that the slopes are negative reciprocals of one another. For example, a line with a slope of 2/3 and another line with a slope of -3/2 has these two values multiply to -1; therefore showing they are perpendicular lines.

7 0

3 years ago

Read 2 more answers

A psychologist is interested in knowing whether adults who were bullied as children differ from the general population in terms

MissTica

Answer:

$t = \frac{39.5-30.6}{\frac{6.6}{\sqrt{25}}}= 6.74$

The degrees of freedom are given by:

$df =n-1= 25-1=24$

Now we can calculate the p value with the following probability:

$p_v = 2*P(t_{24}>6.74)= 5.69x10^{-7}$

And for this case since the p value is lower compared to the significance level $\alpha=0.05$ we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05

Step-by-step explanation:

For this case we have the following info given:

$\bar X = 39.5$ represent the sample mean

$s =6.6$ represent the sample deviation

$\mu = 30.6$ represent the reference value to test.

$n = 25$ represent the sample size selected

The statistic for this case is given by:

$t =\frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

And replacing we got:

$t = \frac{39.5-30.6}{\frac{6.6}{\sqrt{25}}}= 6.74$

The degrees of freedom are given by:

$df =n-1= 25-1=24$

Now we can calculate the p value with the following probability:

$p_v = 2*P(t_{24}>6.74)= 5.69x10^{-7}$

And for this case since the p value is lower compared to the significance level $\alpha=0.05$ we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05

3 0

3 years ago

Which is a valid proportion?

Bumek [7]

Answer:

3/4=21/28

Step-by-step explanation:

21/28÷7/7=3/4

8 0

3 years ago

Create a function rule for the following: x 0 3 6 f(x) -5 -3 -1 lmk asapppp please