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3 years ago

9

Mr. Seidel filled up his 14 gallon gas tank for 29.26. What was the price per gallon?

2 answers:

EleoNora [17]3 years ago

8 0

$29.26 divided by 14= $2.09

mr_godi [17]3 years ago

6 0

It would be $2.09 if you are dividing

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A certain animated movie earned $1.1*10^9 in revenues at the box office. The movie lasts 9.1*10^1 minutes. How much revenue was

Vadim26 [7]

Answer:

$12,087,912.1

Step-by-step explanation:

$1.1*10^9$ is in scientific notation, to get this into normal number, we take the decimal point and move it "9" times to the right [whatever power of 10 we have, we move to right (if positive).] Then we fillup the rest with zeros.

So we have:

$1.1*10^9=1,100,000,000$

This is the revenue.

We do similar process for time:

$9.1*10^1=91$

This is the time , in minutes.

We want revenue PER minute, that means we divide the total revenue by total time, that would be:

$\frac{1,100,000,000}{91}=12,087,912.1$

The revenue earned per minute is $12,087,912.1

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3 years ago

Victoria recently switched to a new electric company. If she uses between 0 and 400 kilowatt-hours (kWh) of electricity per mont

Gekata [30.6K]

Answer:

see the explanation

Step-by-step explanation:

<em><u>The question is </u></em>

Identify the domain and the range, using words and inequalities

Let

x -----> the number of kilowatt-hours (kWh) of electricity per month

y ----> the price per month

we know that

Part 1) For the value of x between 0 kWh and 400 kWh

$0\ kWh \leq x < 400\ kWh$

The price is equal to

$y=\$30$

therefore

The domain is the interval ------> [0,400)

The domain is all real numbers greater than or equal to 0 kWh and less than 400 kWh

The range is ($30)

The range is equal to $30

Part 2) For the value of x equal to 400 kWh or more per month

$x\geq 400\ kWh$

The domain is the interval -----> [400, infinite)

The domain is all real numbers greater than or equal to 400 kWh

The price is

$y=0.097x$

<em>Find the range</em>

For x=400 kWh

$y=0.097(400)=\$38.8$

so

$y\geq \$38.8$

The range is the interval -----> [38.8, infinite)

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3 years ago

What is the value of 5-8×(7-15+8)

salantis [7]

Answer:

I'm pretty sure that the answer is 5. Correct me if i'm wrong

Step-by-step explanation:

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3 years ago

A contractor bought 7.6 ft squared of sheet metal. She has used 4.9 ft squared so far and has $43.20 worth of sheet metal remai

Karo-lina-s [1.5K]

Answer:

$16 per square foot

Step-by-step explanation:

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3 years ago

Read 2 more answers

4. A random variable X has a mean of 10 and a standard deviation of 3. If 2 is added to each value of X, what will the new mean

Ede4ka [16]

Adding 2 to each value of the random variable $X$ makes a new random variable $X+2$ . Its mean would be

$E[X+2]=E[X]+E[2]=E[X]+2$

since expectation is linear, and the expected value of a constant is that constant. $E[X]$ is the mean of $X$ , so the new mean would be

$E[X+2]=10+2=12$

The variance of a random variable $X$ is

$V[X]=E[X^2]-E[X]^2$

so the variance of $X+2$ would be

$V[X+2]=E[(X+2)^2]-E[X+2]^2$

We already know $E[X+2]=12$ , so simplifying above, we get

$V[X+2]=E[X^2+4X+4]-12^2$

$V[X+2]=E[X^2]+4E[X]+4-12^2$

$V[X+2]=(V[X]+E[X]^2)+4E[X]-140$

Standard deviation is the square root of variance, so $V[X]=3^2=9$ .

$\implies V[X+2]=(9+10^2)+4(10)-140=9$

so the standard deviation remains unchanged at 3.

NB: More generally, the variance of $aX+b$ for $a,b\in\mathbb R$ is

$V[aX+b]=a^2V[X]+b^2V[1]$

but the variance of a constant is 0. In this case, $a=1$ , so we're left with $V[X+2]=V[X]$ , as expected.

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4 years ago