Answer:
41.67% probability that a student has a dog given that they have a cat
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: having a cat.
Event B: having a dog.
12 of 27 students have a cat:
This means that 
5 students who have a cat and a dog.
This means that 
What is the probability that a student has a dog given that they have a cat?

41.67% probability that a student has a dog given that they have a cat
Answer:
D. -19/2
Step-by-step explanation:
Well, we know that R is greater than Y and that at the midpoint, R is 10.5, so Y can't be greater than this (c, 13) and that it isn't the same (b, 10.5). It could either be -8 or -19/2 (which is -9.5). Being that your first coordinate is in fraction form, the second one would also have the be, making the answer D. -19/2
-27x - 60 > 15x - 20
+27x +20 +27x +20
-40= 42x
-20
----- = x Is this correct?
21
You can rewrite the inequality as

Note that

is the equation of the line drawn in the pictures. This means that, for every point on the line, the y coordinate is exactly image of the x coordinate, i.e. 
The inequality is satisfied by all points whose y coordinate exceeds the image of the x coordinate. Since the y axis is positively oriented upwards, a greater value for the y coordinate means that the point has to be higher than the line.
Also, since the equality inlves a
and not a
sign, the line itself is excluded.
So, the correct graph is the second one.