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Rudiy27
3 years ago
6

Hal forgot the number of people at the basketball game. He does remember that the number had four digits and a 3 in the tens pla

ce. Write a number that Hal could be thinking of
Mathematics
1 answer:
neonofarm [45]3 years ago
7 0
He could be thinking of 5,637 people at the game
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Given m \\ n find the value of x and y
Jlenok [28]

These are the answers :-

<u>x°</u> <u>=</u> <u>47°</u> (Alternate angles are equal)

<u>y°</u><u> </u><u>=</u><u> </u><u>4</u><u>7</u><u>°</u> (Corresponding angles are equal)

<em>Hope</em><em> this</em><em> helps</em>

5 0
2 years ago
How many different 5​-letter radio station call letters can be made a. if the first letter must be Upper C comma Upper X comma U
Lady_Fox [76]

Answer:

a) 1,518,000

b) 2,284,880

c) 60,720

Step-by-step explanation:

a) a. if the first letter must be Upper C comma Upper X comma Upper T comma or Upper M and no letter may be​ repeated?

We draw 5 boxes, and based on that we will see the total possible cases. There are 26 alphabets

The first box should have C or X or T or M .No letter may be repeated.

Any                    Any             Any                 Any                    Any

5 alphabets    of the            of the              of the                 of the

C,X , T , M      remaining     remaining       remaining          remaining

                   25 alphabets   24 alphabets   23 alphabets   22 alphabets

Therefore; total possible call letters = 5 × 25 × 24 × 23 × 22 = 1,518,000

b)

The first box should have C or X or T or M Repeats as allowed

Any                    Any             Any                 Any                    Any

5 alphabets    of the            of the              of the                 of the

C,X , T , M      remaining     remaining       remaining          remaining

                   26 alphabets   26 alphabets   26 alphabets   26 alphabets

Therefore Total possible call letters = 5 × 26 × 26 × 26 × 26 = 2,284,880

c)   The first box should have   C,X , T , M  and end with S

So the last place if fixed, and we now have 25 alphabets. The first box can go in 5 ways. The next box then will have only 24 letters to choose from, as the first box has taken a letter and the last box already has S in it. Repetition not allowed

Any                    Any             Any                 Any                       S

5 alphabets    of the            of the              of the                  is fixed

C,X , T , M      remaining     remaining       remaining           here

                   24 alphabets   23 alphabets   22 alphabets  

Therefore Total possible call letters = 5 × 24 × 23 × 22  × 1 =  60,720

3 0
3 years ago
PLZ HELP! Use technology or a z-score table to answer the question.
Rashid [163]

Answer:

the answer would be A, or 5.3%

Step-by-step explanation:

you start by finding the z-score of 200, so 200-144.05 = 55.95/34.52 = 1.62 (rounded to the nearest ) Then you use a z-score table to find the probability that a customer will spend less than 200 dollars and subtract the decimal probability from one. then you convert the decimal probability to a percent and get 5.3%.

7 0
2 years ago
Rectangle OPEN has diagonals intersecting at S. If m∠ENP=42 find m∠ EON, m∠ONP, m∠OSP, and m∠PSE
poizon [28]

Answer:

m∠EON = 48°

m∠ONP = 48°

m∠PSE = 90°

4 0
2 years ago
HELPPPPP PLEASE WITH THIS
natulia [17]
0.000000000224 i think thats the answer could be wrong
7 0
3 years ago
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