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Gekata [30.6K]
3 years ago
12

If the perimeter of a rectangle is 38 inches how tall is it

Mathematics
1 answer:
Leni [432]3 years ago
7 0
P = 2l + 2w 
<span>38 = 2l + 2w </span>
<span>l = w + 3 , (the length is 3 inches more than the width) </span>

<span>then substitute w + 3 to l in 38 = 2l + 2w </span>


<span>38 = 2(w + 3) + 2w </span>

<span>38 = 2w + 6 + 2w </span>

<span>38 = 4w + 6, then take away 6 from both sides </span>

<span>32 = 4w, then divide both sides by 4 </span>

<span>w = 8 inches (width)</span>
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Step-by-step explanation:

So if you count the boxes of segment BC you will get 8, same for if you count the boxes that make up segment AD. If they are the same distance they are congruent. You can see how BC and AD are both horizontal lines. To find the slope you need to do the slope formula for BC and AD, which is y2-y1/x2-x1 in our case BC= 4-4/12-4 which equals 0/8. If you do the same formula for AD, you will get 0/8 making them congruent and the slope 0. If the opposite sides are congruent and parallel it has to be a parallelogram by the opposites and congruent theorem.

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