Someone help plz plz

Mathematics

2 answers:

Rashid [163]3 years ago

6 0

Answer:

Step-by-step explanation:

don't start with 2, start with 0

AveGali [126]3 years ago

4 0

Answer:

Step-by-step explanation:

the graph is going by two. since you start with 2 and end at 10 its 8.

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The graph of a line passes through the two points (-2,1) and (2,1)

Vinil7 [7]

Answer: if you graph these points, you'll see that the line is horizontal, so the slope is zero. It will cross the y axis (y intercept) at y=1.

Step-by-step explanation:

Slope = y2-y1/x2-x1, so in this example:

m = 1-1/it doesn't matter because the answer will be zero!!

Now for slope intercept form:

y = mx + b

y = 0x + b; take one of your points and plug it in:

1= 0(2)+ b

1=0 + b

1=b

So your equation is:

y= 0(x) + 1

y=1

8 0

3 years ago

Find sin(2x), cos(2x), and tan(2x) from the given information.

larisa86 [58]

Since $\cot(x)=\frac{2}{3}$ and $\cot^{2} x+1=\csc^{2} x$ , we know that:

$\left(\frac{2}{3} \right)^{2}+1=\csc^{2} x\\\\\frac{13}{9}=\csc^{2} x\\\\\csc x=\frac{\sqrt{13}}{3}$

If $\csc x=\frac{\sqrt{13}}{3}$ , this means that $\sin x=\frac{3}{\sqrt{13}}$ and by the Pythagorean identity,

$\sin^{2} x+\cos^{2} x=1\\\left(\frac{3}{\sqrt{13}} \right)^{2}+\cos^{2} x=1\\\frac{9}{13}+\cos^{2} x=1\\\cos^{2} x=\frac{4}13}\\\cos x=\frac{2}{\sqrt{13}}$

Using the double angle formula for sine, $\sin(2x)=2\left(\frac{3}{\sqrt{13}} \right)\left(\frac{2}{\sqrt{13}} \right)=\boxed{\frac{12}{13}}$
Using the double angle formula for cosine, $\cos(2x)=1-2\left(\frac{3}{\sqrt{13}} \right)^{2}=\boxed{-\frac{5}{13}}$
So, since tan=sin/cos, $\tan (2x)=\frac{\sin(2x)}{\cos(2x)}=\frac{\frac{12}{13}}{-\frac{5}{13}}=\boxed{-\frac{12}{5}}$