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horrorfan [7]
3 years ago
10

PLSSSS HELLLPPPPPPP How much would it cost to buy 3.4 pounds of Bartlett pears and 2.1 pounds of Concorde pears? Concorde pears

$3 per pound Osband pears $3 per pound green Anjou pears $4 per pound Bartlett pears $2 per pound red Anjou pears $5 per pound​

Mathematics
1 answer:
kirill [66]3 years ago
5 0

Answer:

$13.10

Step-by-step explanation:

Concard    $3.00  2.1    $6.30

Osband    $3.00  

Green Anjou  $4.00  

Bartlett          $2.00  3.4     $6.80

Red Anjou  $5.00  

                TOTAL =      $13.10

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You can spend no more than $100 on a party you are hosting. The cost per guest is $8.
ella [17]

Answer:

A.  12 is greater than or equal to x

     

B.  you can invite 12 guests

Step-by-step explanation:

7 0
4 years ago
Solve the equation. Check the solution. Use a graphing calculator.
sergey [27]

Solution

We solve the equation

\begin{gathered} \frac{3}{x+3}+\frac{6}{x-3}=3 \\  \\ Divide\text{ through by 3} \\  \\ \frac{1}{x+3}+\frac{2}{x-3}=1 \\  \\ Clearing\text{ fraction} \\  \\ x-3+2x+6=x^2-9 \\ 3x+3=x^2-9 \\  \\ x^2-3x-12=0 \end{gathered}

We now solve the quadratic equation

\begin{gathered} x^2-3x-12=0 \\  \\ Using\text{ formula method} \\  \\ x=\frac{3\pm\sqrt{3^2-4(1)(-12)}}{2} \\  \\ x=\frac{3\pm\sqrt{9+48}}{2} \\  \\ x=\frac{3\pm\sqrt{57}}{2} \\  \\ Therefore,\text{ the two answers are given below and corrected to two decimal places} \\  \\ x=5.27 \\ and \\ x=-2.27 \end{gathered}

The graph is given below

8 0
2 years ago
Help!!! This is urgent and due today!!!
sasho [114]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Decide whether Rolle's Theorem can be applied to f(x) = x2 + 5 on the interval [0, 3]. If Rolle's Theorem can be applied, find a
kap26 [50]
F(x)= x² + 5, is just a parabola shfited upwards by 5 units, so, is a smooth graph and no abrupt edges, so from 0 to 3, is indeed differentiable and continuous.  So Rolle's theorem applies, let's check for "c" by simply setting its variable to 0, bear in mind that, looking for "c" in this context, is really just looking for a critical point, since we're just looking where f'(c) = 0, and is a horizontal tangent line.

\bf f(x)=x^2+5\implies \cfrac{df}{dx}=2x\implies 0=2x\implies \boxed{0=x}\leftarrow c
7 0
4 years ago
your friend says the greater common factor of 15 and 30 is 5 is your friend cprrect explain ur reasoning
rusak2 [61]
Short Answer:

Yes, the friend is correct.


Answer:

Factors of 15: 1, 3, 5, 15.

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30.



Explanation:

5 • 3 = 15

5 • 6 = 30
3 0
3 years ago
Read 2 more answers
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