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bogdanovich [222]
3 years ago
9

Find sec 0 if 0 is in quadrant IV and sin0=-1/5

Mathematics
1 answer:
WITCHER [35]3 years ago
4 0

Answer:

sec 0 = 5/(2√6)

Step-by-step explanation:

sin 0 = -1/5

Fourth quadrant Cos positive Rest negative

cos²0 + sin²0 = 1

cos²0 = 1-sin²0

cos²0 = 1 - (1/5)²

cos²0 = 1- 1/25

cos²0 = 24/25

cos0 = ±(2√6)/5

quadrant IV cos is positive.

Therefore cos0 = (2√6)/5

Now, sec0 = 1/cos0

sec0 = 1/{(2√6)/5)}

sec0 = 5/(2√6)

.

Hope it helps

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Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

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Finding polynomial by multiply these factors:

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So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

  • brainly.com/question/1464739
  • brainly.com/question/2568692
  • brainly.com/question/10771256

#learnwithBrainly

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