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goldenfox [79]
3 years ago
6

EXTRA POINTS I need helpppp right nowww please help i need help extra points for this i need 100% okay -------------------------

------------------------- now that the admins are gone describe your day for free points
Mathematics
2 answers:
Alex73 [517]3 years ago
7 0

Answer:

It was ordinary

Step-by-step explanation:

professor190 [17]3 years ago
4 0

What makes an excellent each day habitual?

There are not any rules approximately how many or what kind of exercises you need to have. All households are different, and what works well for one circle of relatives may not work for another.

Your routines want to be based on your person circle of relatives needs. But powerful workouts do share 3 key features:

Well planned: in an excellent ordinary, every person knows their roles, is aware of what they want to do, and sees their roles as affordable and fair. For example, your youngsters understand that they take turns washing up and drying up each night after dinner.

Regular: true exercises become a part of ordinary circle of relatives life. For example, you would possibly all sit up for Sunday night time barbecues with your kids’s grandparents.

Predictable: in a terrific recurring, matters happen inside the identical order each time. For example, you always wash college uniforms at the weekend, so you recognise they’ll be geared up for Monday morning.

Toddlers and preschoolers: ideas for daily exercises

For toddlers and preschoolers, you may have workouts for:

getting prepared within the morning

getting together with different youngsters to play, perhaps at playgroup

ingesting meals

spending time playing and talking together every day

studying books or telling stories

having quiet time and going to mattress at night time.

A bedtime ordinary for infants is probably brushing enamel and converting nappy, having some quiet time while analyzing a book, then getting into bed for a special song and kiss properly night time.

School-age youngsters: thoughts for each day workouts

For school-age children, you can have routines for:

getting prepared inside the morning and going to mattress at night

tidying up toys

getting together with different children to play, perhaps after faculty a couple of times a week

giving out pocket cash at a regular time and day

doing after-faculty activities like pursuits or sport

doing chores – for example, putting the dinner desk, unpacking the dishwasher, assisting with the laundry, or worrying for pets.

For college-age children, you may have a playdate ordinary if there are days when you don’t visit paid paintings. For example, on Mondays, your faculty-age baby is permitted to invite a chum over after college. When the friend is going domestic at approximately 5 pm, your toddler tidies up earlier than putting the desk for dinner.

Teenagers: ideas for day by day routines

Older children and young adults would possibly develop out of, or start to challenge, some exercises. You’ll probably need to be bendy and adapt exercises as your youngsters get older. For example, you may need to exchange bedtime workouts or the chores that youngsters do around the house.

For young adults, you can have routines for:

doing laundry or other chores like making beds and cleansing rooms

doing homework

doing after-college sports, including hobbies or sport.

A weekday evening routine on your teenage child would possibly contain getting domestic from sports training, having a brief shower, sitting all the way down to a own family meal, and then helping with the washing up and clearing away before doing an hour or so of homework.

Routines for the whole family: ideas

You should have exercises for:

getting ready and consuming meals together

spending family time, like everyday walks after dinner or film nights

having family meetings, or simply taking turns speakme approximately the day

spending special one-to-one time with parents

catching up with extended own family and friends

taking component in unique birthday party days or community sports.

please mark me brainliest!

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Suppose that 10 years ago you bought a home for $160,000, paying 10% as a down payment, and financing the rest at 9% interest fo
Goshia [24]

Answer:

Current monthly payment on their existing mortgage would be $1158.66

Step-by-step explanation:

Total cash value = $160,000

Down payment = 10% of 160,000

Down Payment = $16,000

Balance amount = 160,000 - 16,000 = $144,000

Monthly payment formula:

P=\dfrac{r(PV)}{1-(1+r)^{-n}}

where,

PV is present value of home, PV=$144,000

r is rate per period , r=\frac{9}{1200}=0.0075

n is number of period, n=30x12 = 360

P=\dfrac{0.0075\times 144000}{1-(1+0.0075)^{-360}}

P=\$ 1158.66

Monthly payment would be same for 30 years.

Thus, Current monthly payment on their existing mortgage would be $1158.66

5 0
2 years ago
In a wrestling contest, a wrestler needs a winning percentage of at least 70% to qualify for round 2. sam lost 3 out of 12 match
algol [13]
He won about 25% because 6/12 would be 1/2 and 3 is 1/2 of 6 or a 1/4 so 25%
8 0
3 years ago
Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part
katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

(26)x = 1

(50)x = 1

and:

(2^6)^x = 1

(5^0)^x = 1

Solving: (26)x = 1  and  (50)x = 1

(26)x = 1

Divide both sides by 26

x = \frac{1}{26}

(50)x = 1

Divide both sides by 50

x = \frac{1}{50}

Solving (2^6)^x = 1 and (5^0)^x = 1

(2^6)^x = 1

Express 1 as 2^0

(2^6)^x = 2^0

Remove bracket

2^{6x} = 2^0

Cancel out 2

6x = 0

Divide both sides by 6

x = \frac{0}{6}

x = 0

(5^0)^x = 1

Express 1 as 5^0

(5^0)^x = 5^0

Cancel out 5^0

x = 1

8 0
3 years ago
Ivana and Gloria are sisters. Gloria is
Marina CMI [18]

Answer:

11 years old

Step-by-step explanation:

3 years ago, Gloria was 32 years old

If Ivana's age is = x

Then, 4x = 32

            x = 8

3 years ago, Ivana was 8 years old

So now she is 11 years old.

4 0
3 years ago
The game of European roulette slots: 18 red, 18 black, and I green. A ball is spun onto the wheel and will eventually land ina s
Anestetic [448]

Answer:

(a) E(x) = -0.081  S.D = 3

(b) E(x) = -0.081  S.D = 1.73

(c) it is less risky to bet $1 in three different rounds as compared to betting $3 in a single round.    

Step-by-step explanation:

(a) You bet $3 on a single round which means that if you win the game, your amount will double ($6), your profit will be $3. Whereas, if you lose the round, your profit will be -$3. You can only bet on red or black and both have 18 slots each.

So, the probability of landing the ball in a red/black slot = 18/37. This is the probability of winning. The probability of losing can be calculated as 1-18/37 = 19/37.

We can make a probability distribution table:

x                    3             -3

P(X=x)         18/37      19/37

Expected value E(x) can be calculated as:

E(x) = ∑ x.P(x)

      = (3)(18/37) + (-3)(19/37)

E(x) = -0.081

Standard deviation can be calculated by the following formula:

Var(x) = E(x²) - E(x)²

S.D = √Var(x)

We need to first calculate E(x²).

E(x²) = ∑x².P(x)

       = (3)²(18/37) + (-3)²(19/37)

       = (9)(18/37) + (9)(19/37)

E(x²) = 9

Var(x) = E(x²) - E(x)²

         = 9 - (-0.081)²

Var(x) = 8.993

S.D = √8.993

S.D = 2.99 ≅ 3

(b) Now, the betting price is $1 and 3 rounds are played. We will compute the expectation for one round and then add it thrice to find the expectation for three rounds. Similarly, for the standard deviations, we will add the individual variances and then consider the square root of it.

E(x) = ∑ x.P(x)

      = (1)(18/37) + (-1)(19/37)

E(x) = -0.027

Standard deviation can be calculated by the following formula:

Var(x) = E(x²) - E(x)²

S.D = √Var(x)

We need to first calculate E(x²).

E(x²) = ∑x².P(x)

       = (1)²(18/37) + (-1)²(19/37)

       = (1)(18/37) + (1)(19/37)

E(x²) = 1

Var(x) = E(x²) - E(x)²

         = 1 - (-0.027)²

Var(x) = 0.9992

The expectation for one round is -0.027

For three rounds,

E(x₁ + x₂ + x₃) = E(x₁) + E(x₂) + E(x₃)

                     = (-0.027) + (-0.027) + (-0.027)

E(x₁ + x₂ + x₃) = -0.081

Similarly, the variance for one round is 0.9992.

Var (x₁ + x₂ + x₃) = Var(x₁) + Var(x₂) + Var(x₃)

                           = 0.9992 + 0.9992 + 0.9992

Var (x₁ + x₂ + x₃) = 2.9976

S.D = √2.9976

S.D = 1.73              

(c) The expected values for both part (a) and (b) are the same but the standard deviation is lower in part (c) as compared to (b). Since the standard deviation is less in part (c), it means that it is <u>less risky to bet $1 in three different rounds as compared to betting $3 in a single round.</u>            

5 0
3 years ago
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