Answer:
ion k
Step-by-step explanation:
Answer:
B. The graph is linear and has an equation of y = -x + 18
Step-by-step explanation:
if the equation was y = -2x + 18 then the graph would look like a staircase and the graph looks linear
Answer:
Below in bold.
Step-by-step explanation:
If the 3 points are on the circle with the given center then the distance from each point to the center will all be equal. This distance will be the radius of the circle.
Distance of P (2, 5) from the center (4, 2)
= √( (5-2)^2 + (2-4)^2)
= √(9 + 4)
= √13.
For Q (6, -1)this distance is:
= √(6-4)^2 + (-1-2)^2)
= √13.
For R (7, 4) his distance is:
= √(7-4)^2 + (4-2)^2)
= √13
These distances are the same so the points P, Q and R lie on the circle.
The midpoint of PQ
= (2+6)/2 , (5 - 1)/2
= (4, 2).
Which is the center so this verifies the second part.
Answer:
29
Step-by-step explanation:
M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,
timama [110]
Answer:
Step-by-step explanation:
Given
<LON = 77°
<LOM = (9x+44)°
<MON = (6x+3)°
The addition postulate is true for the given angles since tey have a common point O:
<LON = <LOM+<MON
Since we are not told what to find we can as well look for the value of x, <LOM and <MON
Substitute the given parameters and get x
77 = 9x+44+6x+3
77 = 15x+47
77-47 = 15x
30 = 15x
x = 30/15
x = 2
Get <LOM:
<LOM = 9x+44
<LOM = 9(2)+44
<LOM = 18+44
<LOM = 62°
Get <MON:
<MON = 6x+3
<MON = 6(2)+3
<MON = 12+3
<MON = 15°
