Answer:
The correct answer is - B) Elysia Chlorotica grows when exposed to light in the absence of other food sources
Explanation:
If placing Elysia Chlorotica in presence of the food sources in the presence or absence of light it still grows as normal. However, if placing in the light in absence of the food sources it should not grow if it is not able to perform photosynthesis but it does which means there is a photosynthesis process also involve in the Elysia.
Photosynthesis is the process that involves the production of energy and nutrition in presence of light with water and atmospheric carbon dioxide.
When the cell gains glucose, the process of glycolysis occurs and then the glucose is broken down into pyruvate.
Now, in pyruvate processing, Acetyl CoA is produced and used in the Krebs Cycle.
During that process, NADH and FADH2 are made and go into the electron transport chain. That is where water and ATP are made.
The type b intercalated cells will reduce the amount of bicarbonate ion secreted and the amount of hydrogen ions excreted by the body in order to deal with alkalosis.
<h3>What is alkalosis?</h3>
Alkalosis is a condition in which excess alkali is present in the blood.
Alkalosis occurs when the body exceeds excess alkali in from the body.
Therefore, the type b intercalated cells will reduce the amount of bicarbonate ions secreted and the amount of hydrogen ions excreted by the body in order to deal with alkalosis.
Learn more about alkalosis at: brainly.com/question/14971300
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They use to determine weather
From the intake verses goals reports, Reuben ate 72-54 g total Fat. The DV for total fat from the nutrition facts panel (food label) is 65 g; 72.54(65 ) ×100
= 111% DV for total fat.
Too much saturated fat may raise the amount of cholesterol in blood, which can increase the risk of heart disease, thus one should consume no more than the recommended daily intake.
