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max2010maxim [7]
4 years ago
13

Create a dictionary password cracker or a brute force

Computers and Technology
1 answer:
Margaret [11]4 years ago
4 0

Answer:

So if someone is smart enough to keep a safe password this tool will help you with it. Pydictor is written in python. There is two method to crack the password using this tool one creates a normal wordlist the other creates wordlist in base64 form. We will try both methods.

Explanation:

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Directions: Using the decoder key and the code chart on the second page, find out the name that has been coded. After coding the
Karo-lina-s [1.5K]

What is the decodder key???

7 0
4 years ago
How do you record your own video game Music and post Them on yt
Alex777 [14]

Answer:I would try downloading a beat app and making a song,then posting

Explanation:

8 0
3 years ago
Read 2 more answers
The function below takes two integer parameters: low and high. Complete the function so that it prints the numbers from low to h
NikAS [45]

Answer:

def print_range(low, high):

 for i in range(low,high):

   print(i)

Explanation:

Create the function to accept two parameters (low and high)

Use a for loop to iterate from low to high using the range function

Print the value at each iteration

See a complete program and output below.

<em>def print_range(low, high): </em>

<em>  for i in range(low,high):</em>

<em>    print(i)</em>

<em>low = 1</em>

<em>high =10</em>

<em>print_range(low, (high+1)) </em>

<em />

5 0
4 years ago
Write a program that uses two input statements to get two words as input. Then, print the words on one line separated by a space
Shkiper50 [21]

word1 = input("Enter a word: ")

word2 = input("Enter a word: ")

print(word1 + " " + word2)

I hope this helps!

6 0
3 years ago
Write an if/else statement that compares the double variable pH with 7.0 and makes the following assignments to the int variable
Brilliant_brown [7]

Answer:

int main()

{

   double pH;

   int neutral;

   int base;

   int acid;

   cout<<"Enter a pH Value";

   cin>> pH;

   if(pH<7.0){

       neutral =0;

       base=0;

       acid= 1;

   }

   else if (pH=7.0){

       neutral =1;

       base=0;

       acid= 0;

   }

   else{

       neutral =0;

       base=1;

       acid= 0;

   }

   cout <<"The neutral, Base and Acid Values are: "<<neutral<<","<<base<<","<<acid<<" Respectively"<<endl;

   return 0;

}

Explanation:

Using multiple if/elseif/else statement the following problem is solved with C++

4 0
3 years ago
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