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max2010maxim [7]
3 years ago
13

Create a dictionary password cracker or a brute force

Computers and Technology
1 answer:
Margaret [11]3 years ago
4 0

Answer:

So if someone is smart enough to keep a safe password this tool will help you with it. Pydictor is written in python. There is two method to crack the password using this tool one creates a normal wordlist the other creates wordlist in base64 form. We will try both methods.

Explanation:

You might be interested in
2.36 LAB: Warm up: Variables, input, and casting (1) Prompt the user to input an integer, a double, a character, and a string, s
Westkost [7]

Answer:

The entire program is:

#include <iostream>

using namespace std;

  int main() {          

  int userInt;

  double userDouble;

  char userChar;

  string userString;  

  cout<<"Enter integer:"<<endl;

  cin>>userInt;  

  cout<<"Enter double:"<<endl;

  cin>>userDouble;  

  cout<<"Enter character:"<<endl;

  cin>>userChar;  

  cout<<"Enter string:"<<endl;

  cin>>userString;    

 cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl;

 cout<<endl;  

   cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt<<endl;  

cout<<endl;

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt<<endl<<userDouble<<" cast to an integer is "<<(int)userDouble;  

  return 0;  }

The program in C language:

#include <stdio.h>  

int main() {

  int userInt;  

  double userDouble;  

  char userChar;  

  char userString[50];

  printf("Enter integer: \n");  

  scanf("%d", &userInt);

  printf("Enter double: \n");  

  scanf("%lf", &userDouble);

  printf("Enter character: \n");  

  scanf(" %c", &userChar);  

  printf("Enter string: \n");  

  scanf("%s", userString);  

  printf("%d %lf %c %s\n", userInt, userDouble, userChar, userString);

  printf("\n");

  printf("%d %lf %c %s\n%s %c %lf %d \n", userInt, userDouble, userChar, userString, userString, userChar, userDouble, userInt);

  printf("\n");

  printf("%d %lf %c %s\n%s %c %lf %d\n%lf cast to an integer is %d \n", userInt, userDouble, userChar, userString, userString, userChar, userDouble, userInt, userDouble, (int)userDouble);  }

Explanation:

Lets do the program step by step:

1)  Prompt the user to input an integer, a double, a character, and a string, storing each into separate variables. Then, output those four values on a single line separated by a space:

Solution:

The program is:

#include <iostream>  //to use input output functions

using namespace std;  //to identify objects cin cout

  int main() {  //start of main method

  //declare an integer, a double, a character and a string variable  

  int userInt;  //int type variable to store integer

  double userDouble;  //double type variable to store double precision floating point number

  char userChar;  //char type variable to store character

  string userString;  //string type variable to store a string

  cout<<"Enter integer:"<<endl;  //prompts user to enter an integer

  cin>>userInt;  //reads the input integer and store it to userInt variable

  cout<<"Enter double:"<<endl;  //prompts user to enter a double type value

  cin>>userDouble;  //reads the input double value and store it to userDouble variable

  cout<<"Enter character:"<<endl;  //prompts user to enter a character

 cin>>userChar; //reads the input character and store it to userChar variable

  cout<<"Enter string:"<<endl;  //prompts user to enter a string

  cin>>userString; //reads the input string and store it to userString variable

   

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl; //output the values on a single line separated by space

So the output of the entire program is:

Enter integer:                                                                                                                                99                                                                                                                                            Enter double:                                                                                                                                 3.77                                                                                                                                          Enter character:                                                                                                                              z                                                                                                                                             Enter string:                                                                                                                                 Howdy                                                                                                                                         99 3.77 z Howdy

(2) Extend to also output in reverse.

Now the above code remains the same but add this output (cout) statement at the end:

  cout<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt;

Now the output with the same values given as input is:

Enter integer:                                                                                                                                  99                                                                                                                                              Enter double:                                                                                                                                   3.77                                                                                                                                            Enter character:                                                                                                                                z                                                                                                                                               Enter string:                                                                                                                                   Howdy  

99 3.77 z Howdy                                                                                                                                     Howdy z 3.77 99

(3) Extend to cast the double to an integer, and output that integer.

The rest of the code remains the same but add the following output (cout) statement in the end:

cout<<userDouble<<" cast to an integer is "<<(int)userDouble;

Now the output with the same values given as input is:

Enter integer:                                                                                                                                  99                                                                                                                                              Enter double:                                                                                                                                   3.77                                                                                                                                            Enter character:                                                                                                                                z                                                                                                                                               Enter string:                                                                                                                                   Howdy                                                                                                                                           99 3.77 z Howdy                                                                                                                                 Howdy z 3.77 99                                                                                                                                 3.77 cast to an integer is 3  

3 0
3 years ago
Translate each of these statements into logical expressions using predicates, quantifiers, and logical connectives. a) Something
yKpoI14uk [10]

Answer:

Let P(x) = x is in the correct place

Let Q(x) =  x is in the excellent place

R(x) denotes the tool

Explanation:

a) Something is not in the correct place.

P(x) is that x is in the correct place so negation of ¬P(x) will represent x is not in the correct place. ∃x is an existential quantifier used to represent "for some" and depicts something in the given statement. This statement can be translated into logical expression as follows:

                                                    ∃x¬P(x)

b) All tools are in the correct place and are in excellent condition.

R(x) represents the tool, P(x) represents x is in correct place and Q(x) shows x is in excellent place. ∀ is used to show that "all" tools and ∧ is used here because tools are in correct place AND are in excellent condition so it depicts both P(x) and Q(x). This statement can be translated into logical expression as follows:

                                       ∀ x ( R(x) → (P(x) ∧ Q(x))

c) Everything is in the correct place and in excellent condition.

Here P(x) represents correct place and Q(x) represents excellent condition ∀ represent all and here everything. ∧  means that both the P(x) and Q(x) exist. This statement can be translated into logical expression as follows:

                                              ∀ x (P(x) ∧ Q(x)

7 0
3 years ago
All organizations with a router at the boundary between the organization’s internal networks and the external service provider w
Anika [276]

Answer:

False

Explanation:

Access Control Lists (ACLs) are network filters used by routers and some switches to permit and restrict data flows in and out of network devices. When an ACL is implemented in a device or interface, the network device analyses data passing through it, compares it to the specification described in the ACL, and allows it the data to flow or prohibits it. One of the main reasons ACLs arre used is to provide a basic level of security for networks. If anything, the use of ACLs and their complexities bring about a delay in transmission through networks.

3 0
3 years ago
This component is responsible for the logical order of processing?
Svetradugi [14.3K]

Answer:

A) ALU

Explanation:

The arithmetic logic unit (ALU) performs the arithmetic and logical functions that are the work of the computer.

So, the correct option is - A) ALU

6 0
3 years ago
OSHA standards appear in the ___________ and are then broken down into ____________.
miskamm [114]
OSHA standards appear in the <span>Code of Federal Regulations (CFR) and are then broken down into Parts</span>
3 0
3 years ago
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