Solution :
a). The two arrays that are used in parallel in order to store the identification of two numbers of 5 employees and their weekly gross payments is :
int id_array[5];
double gross_pay[5];
b). The loop that uses the arrays for printing the identification number and the weekly gross payment is given below :
for(int i=0; i<5; i++)
{
count <<id_array[i] <<" " << gross_pay[i] << end;
}
Answer:
200 Ω
Explanation:
Hi there!
Please see below for the circuit diagram.
<u>1) Find the total resistance of the resistors in parallel</u>
Total resistance in parallel equation: 
Both the resistors measure 200 Ω. Plug these into the equation as R₁ and R₂:
Therefore, the total resistance of the resistors in parallel is 100 Ω.
<u>2) Find the total resistance of the circuit</u>
Now, to find the total resistance of the circuit, we must add the 100 Ω we just solved for and the 100 Ω for the other resistor placed in series:
100 Ω + 100 Ω = 200 Ω
Therefore, the total resistance of the circuit is 200 Ω.
I hope this helps!
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Answer:
Explanation:
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