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Paladinen [302]
3 years ago
11

What is the slope of the line?

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

The slope of the line must be 3

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

step 1

we know that

The volume of a rectangular prism is equal to

V_r_p=Bh ----> equation A

where

B is the area of the base of the prism

h is the height of the rectangular prism

step 2

The volume of a square pyramid is equal to

V_s_p=\frac{1}{3}Bh -----> equation B

where

B is the area of the square base of pyramid

h is the height of the pyramid

step 3

substitute equation A in equation B

V_s_p=\frac{1}{3}V_r_p

Find the relationship between the volume of  a rectangular prism and the volume of a square pyramid

\frac{V_r_p}{V_s_p}=3

therefore

The slope of the line must be 3

let's check it

To solve for the slope of the line, you must choose two coordinates first and use the formula

m=\frac{y2-y1}{x2-x1}

Choosing the points (2,6) and (3,9)

substitute

m=\frac{9-6}{3-2}=3 ----> is correct

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What are the soulutions to m^2-9=0
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Step-by-step explanation:

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Read 2 more answers
Points A and B have coordinates (3,1,2) and (1,-5,4) respectively. Point C lies on line AB such that AC:BC=3:2. Find position ve
Sever21 [200]

Answer:

The position vector of point C is <-3 , -17 , 8> or -3i - 17j + 8k

Step-by-step explanation:

* Lets revise how to solve the problem

- If the endpoints of a segment are (x1 , y1 , z1) and (x2 , y2 , z2), and

 point (x , y , z) divides the segment externally at ratio m1 :m2, then

 x=\frac{m_{1}x_{2}-m_{2}x_{1}}{m_{1} -m_{2}},y=\frac{m_{1}y_{2}-m_{2}y_{1}}{m_{1}-m_{2}},z=\frac{m_{1}z_{2}-m_{2}z_{1}}{m_{1}-m_{2}}

* Lets solve the problem

∵ AB is a segment where A = (3 , 1 , 2) and B = (1 , - 5 , 4)

∵ Point C lies on line AB such that AC : BC=3 : 2

∵ From the ratio AC = 3/2 AB

∴ C divides AB externally

- Lets use the rule above to find the coordinates of C

- Let Point A is (x1 , y1 , z1) , point B is (x2 , y2 , z2) and point C is (x , y , z)

 and AC : AB is m1 : m2

∴ x1 = 3 , x2 = 1

∴ y1 = 1 , y2 = -5

∴ z1 = 2 , z2 = 4

∴ m1 = 3 , m2 = 2

- By using the rule above

∴ x=\frac{3(1)-2(3)}{3-2}=\frac{3-6}{1}=\frac{-3}{1}=-3

∴ y=\frac{3(-5)-2(1)}{3-2}=\frac{x=-15-2}{1}=\frac{-17}{1}=-17

∴ z=\frac{3(4)-2(2)}{3-2}=\frac{12-4}{1}=\frac{8}{1}=8

∴ The coordinates fo point c are (-3 , -17 , 8)

* The position vector of point C is <-3 , -17 , 8> or -3i - 17j + 8k

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3 years ago
Find the LCM of the set of numbers: 9, 13
expeople1 [14]

Answer:

117

Step-by-step explanation:

prime factors of 9 are 3 and 3

prime factor of 13 is 13

multiply them

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2 years ago
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