A building has an entry the shape of a parabolic arch 84 ft high and 42 ft wide at the base, as shown below. A parabola opening

Question

3 years ago

8

A building has an entry the shape of a parabolic arch 84 ft high and 42 ft wide at the base, as shown below. A parabola opening

down with vertex at the origin is graphed on the coordinate plane. The height of the parabola from top to bottom is 84 feet and its width from left to right is 42 feet. Find an equation for the parabola if the vertex is put at the origin of the coordinate system. (

Mathematics

2 answers:

Grace [21] · Answer 1 · 2022-04-25T00:52:13+03:00

Grace [21]3 years ago

6 0

Answer:

x² = -21y

Step-by-step explanation:

THIS IS THE RIGHT ANSWER I TOOK THE TEST

lara [203] · Answer 2 · 2022-04-24T23:10:41+03:00

Answer:

Step-by-step explanation:

Because of the nature of the information we are given, we have no choice but to use the equation

$y=a(x-h)^2+k$

and solve for a.

We know by the info that the vertex is (0, 84). We also know that if the vertex is at the origin, and that the base is 42 feet wide, it spans 21 feet to the right of the origin and 21 feet to the left of the origin. That means that we have 2 coordinates from which we need to pick one for our x and y in the equation. I don't like negatives, so I am going to choose the coordinate (21, 0) as x and y. Because this parabola opens upside down, as archways of door openings do, our "a" value better come out algebraically as a negative. Let's see...From the vertex we have that h = 0 and k = 84. So filling in:

$0=a(21-0)^2+84$ and simplifying a bit:

0 = 441a + 84 and

-84 = 441a so

$a=-\frac{84}{441}=-\frac{4}{21}$ Good, a is negative. Your equation is, then:

$y=-\frac{4}{21}x^2+84$