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3 years ago

Which of these triangles appears not to be congruent to any others shown

Mathematics

2 answers:

Romashka [77]3 years ago

7 0

Answer:

Options (B) and (D)

Step-by-step explanation:

If two triangles have the same size and shape they are said to be congruent triangles.

Triangles given in the attachment,

Triangles A and E appear to be congruent.

And triangles C and F appear to be congruent.

[Since corresponding sides of these triangles don't appear to be the same in measure]

Remaining triangles B and D do not appear to be congruent.

Therefore, Options (B) and (D) will be the answer.

Sergio039 [100]3 years ago

5 0

Answer: Triangle A & Triangle B

Answer for Apex ^^

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2+2+2+2+2+2+2+206+737472

taurus [48]

Answer:

737714

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3 years ago

Read 2 more answers

Using the Associative Property which expression is equivalent to (2+x)+4=

Anna35 [415]

Answer:

x+6

Step-by-step explanation:

The given expression is (2+x)+4.

The associative property is :

(a+b)+c= a+(b+c)

Here,

a = 2, b = x and c = 4

So,

(2+x)+4 = 2+(x+4)

= x+6

So, the equivalent expression is x+6.

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3 years ago

A triangle has the coordinates

fiasKO [112]

Answer:

coordinates of its image

A' = ( -4, -1)

B' =( -3, -3)

C' = ( 0, 2)

Step-by-step explanation:

Reflect in y-axis means mirror it's points in the y -axis.

This means that the x coordinate of each point, changes only. Any mirrored point in the y-axis, will change only, by multiplying the x-coordinate by -1.

(Remember, zero multiplied by -1 remains 0).

Given are these points A, B, and C.

A = (4, -1)

B = (3,-3)

C = (0, 2)

After mirroring in the y- axis you get:

A' = ( -4, -1)

B' =( -3, -3)

C' = ( 0, 2)

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3 years ago

A line with slope -2/3 passes through the point (-12,16) What is the X-intercept

Troyanec [42]

to find the x-intercept of a function, we simply set y = 0 and then solve for "x", so, let's first find the equation of it and then set y = 0.

$\bf (\stackrel{x_1}{-12}~,~\stackrel{y_1}{16})~\hspace{10em} slope = m\implies-\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-16=-\cfrac{2}{3}[x-(-12)] \\\\\\ y-16=-\cfrac{2}{3}(x+12)\implies \stackrel{\stackrel{y}{\downarrow }}{0}-16=-\cfrac{2}{3}x-8\implies -8=-\cfrac{2x}{3} \\\\\\ -24=-2x\implies \cfrac{-24}{-2}=x\implies 12=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (12,0) ~\hfill$